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Predict the Product. Provide the stable organic product(s) for the reactions below. OH om NH₂ 1. 1. 1 eq -NH₂ 2. H₂O/ HCI HO pyridine si 1.1 eq 2. H₂O NH₂ 2. H₂O/ HCI (excess) -NH₂

Predict the Product. Provide the stable organic product(s) for the reactions below. OH om NH₂ 1. 1. 1 eq -NH₂ 2. H₂O/ HCI HO pyridine si 1.1 eq 2. H₂O NH₂ 2. H₂O/ HCI (excess) -NH₂

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Predict the Product. Provide the stable organic product(s) for the reactions below. #### Reaction 1: **Reactants:** - A five-membered lactone with a ketone and ester group. - 1 equivalent of an amine with an alkyne group (propen-2-amine). - Water/HCl (Hydrochloric acid aqueous solution). **Instructions:** 1. Combine the lactone with the amine in equimolar amounts. 2. Follow the reaction with the addition of water and hydrochloric acid. **Expected Product:** - The stable organic product will be an amide formed by the reaction of the ester with the amine, followed by hydrolysis of the remaining ester group to a carboxylic acid. #### Reaction 2: **Reactants:** - Propanoyl chloride (an acyl chloride). - 4-Hydroxy-THF (tetrahydrofuran) in the presence of pyridine (a base). **Instructions:** 1. React propanoyl chloride with 4-Hydroxy-THF. 2. Pyridine is used as a base to neutralize the product. **Expected Product:** - The stable organic product will be an ester formed by the reaction of the hydroxyl group of 4-Hydroxy-THF with the acyl chloride. #### Reaction 3: **Reactants:** - 4-Amino-2-hydroxybenzoic acid (salicylamide). - An excessive amount of acetic anhydride. - Water. **Instructions:** 1. React salicylamide with an excessive amount of acetic anhydride. 2. Add water to the reaction mixture. **Expected Product:** - The stable organic product will be an acetylated amide and ester. The hydroxyl and amino groups will react with acetic anhydride to form acetate esters. #### Reaction 4: **Reactants:** - A five-membered cyclic imide. - 1 equivalent of a diamine (pyrrolidine-2,5-diamine). - Water/HCl (Hydrochloric acid aqueous solution). **Instructions:** 1. Combine the cyclic imide with the diamine in equimolar amounts. 2. Follow the reaction with the addition of water and hydrochloric acid. **Expected Product:** - The stable organic product will be a ring-opened
Transcribed Image Text:### Predict the Product. Provide the stable organic product(s) for the reactions below. #### Reaction 1: **Reactants:** - A five-membered lactone with a ketone and ester group. - 1 equivalent of an amine with an alkyne group (propen-2-amine). - Water/HCl (Hydrochloric acid aqueous solution). **Instructions:** 1. Combine the lactone with the amine in equimolar amounts. 2. Follow the reaction with the addition of water and hydrochloric acid. **Expected Product:** - The stable organic product will be an amide formed by the reaction of the ester with the amine, followed by hydrolysis of the remaining ester group to a carboxylic acid. #### Reaction 2: **Reactants:** - Propanoyl chloride (an acyl chloride). - 4-Hydroxy-THF (tetrahydrofuran) in the presence of pyridine (a base). **Instructions:** 1. React propanoyl chloride with 4-Hydroxy-THF. 2. Pyridine is used as a base to neutralize the product. **Expected Product:** - The stable organic product will be an ester formed by the reaction of the hydroxyl group of 4-Hydroxy-THF with the acyl chloride. #### Reaction 3: **Reactants:** - 4-Amino-2-hydroxybenzoic acid (salicylamide). - An excessive amount of acetic anhydride. - Water. **Instructions:** 1. React salicylamide with an excessive amount of acetic anhydride. 2. Add water to the reaction mixture. **Expected Product:** - The stable organic product will be an acetylated amide and ester. The hydroxyl and amino groups will react with acetic anhydride to form acetate esters. #### Reaction 4: **Reactants:** - A five-membered cyclic imide. - 1 equivalent of a diamine (pyrrolidine-2,5-diamine). - Water/HCl (Hydrochloric acid aqueous solution). **Instructions:** 1. Combine the cyclic imide with the diamine in equimolar amounts. 2. Follow the reaction with the addition of water and hydrochloric acid. **Expected Product:** - The stable organic product will be a ring-opened
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