### Predict the Product. Provide the stable organic product(s) for the reactions below.#### Reaction 1:**Reactants:**- A five-membered lactone with a ketone and ester group.- 1 equivalent of an amine with an alkyne group (propen-2-amine).- Water/HCl (Hydrochloric acid aqueous solution).**Instructions:**1. Combine the lactone with the amine in equimolar amounts.2. Follow the reaction with the addition of water and hydrochloric acid.**Expected Product:**- The stable organic product will be an amide formed by the reaction of the ester with the amine, followed by hydrolysis of the remaining ester group to a carboxylic acid.#### Reaction 2:**Reactants:**- Propanoyl chloride (an acyl chloride).- 4-Hydroxy-THF (tetrahydrofuran) in the presence of pyridine (a base).**Instructions:**1. React propanoyl chloride with 4-Hydroxy-THF.2. Pyridine is used as a base to neutralize the product.**Expected Product:**- The stable organic product will be an ester formed by the reaction of the hydroxyl group of 4-Hydroxy-THF with the acyl chloride.#### Reaction 3:**Reactants:**- 4-Amino-2-hydroxybenzoic acid (salicylamide).- An excessive amount of acetic anhydride.- Water.**Instructions:**1. React salicylamide with an excessive amount of acetic anhydride.2. Add water to the reaction mixture.**Expected Product:**- The stable organic product will be an acetylated amide and ester. The hydroxyl and amino groups will react with acetic anhydride to form acetate esters.#### Reaction 4:**Reactants:**- A five-membered cyclic imide.- 1 equivalent of a diamine (pyrrolidine-2,5-diamine).- Water/HCl (Hydrochloric acid aqueous solution).**Instructions:**1. Combine the cyclic imide with the diamine in equimolar amounts.2. Follow the reaction with the addition of water and hydrochloric acid.**Expected Product:**- The stable organic product will be a ring-opened

To find: stable product of the given reactions.

Answered: Predict the Product. Provide the stable…

Predict the Product. Provide the stable organic product(s) for the reactions below. OH om NH₂ 1. 1. 1 eq -NH₂ 2. H₂O/ HCI HO pyridine si 1.1 eq 2. H₂O NH₂ 2. H₂O/ HCI (excess) -NH₂

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Catalysis and Enzymatic Reactions

Catalysis is the kind of chemical reaction in which the rate (speed) of a reaction is enhanced by the catalyst which is not consumed during the process of reaction and afterward it is removed when the catalyst is not used to make up the impurity in the product. The enzymatic reaction is the reaction that is catalyzed via enzymes.

Lock And Key Model

The lock-and-key model is used to describe the catalytic enzyme activity, based on the interaction between enzyme and substrate. This model considers the lock as an enzyme and the key as a substrate to explain this model. The concept of how a unique distinct key only can have the access to open a particular lock resembles how the specific substrate can only fit into the particular active site of the enzyme. This is significant in understanding the intermolecular interaction between proteins and plays a vital role in drug interaction.

Question

### Predict the Product. Provide the stable organic product(s) for the reactions below.

#### Reaction 1:
**Reactants:**
- A five-membered lactone with a ketone and ester group.
- 1 equivalent of an amine with an alkyne group (propen-2-amine).
- Water/HCl (Hydrochloric acid aqueous solution).

**Instructions:**
1. Combine the lactone with the amine in equimolar amounts.
2. Follow the reaction with the addition of water and hydrochloric acid.

**Expected Product:**
- The stable organic product will be an amide formed by the reaction of the ester with the amine, followed by hydrolysis of the remaining ester group to a carboxylic acid.

#### Reaction 2:
**Reactants:**
- Propanoyl chloride (an acyl chloride).
- 4-Hydroxy-THF (tetrahydrofuran) in the presence of pyridine (a base).

**Instructions:**
1. React propanoyl chloride with 4-Hydroxy-THF.
2. Pyridine is used as a base to neutralize the product.

**Expected Product:**
- The stable organic product will be an ester formed by the reaction of the hydroxyl group of 4-Hydroxy-THF with the acyl chloride.

#### Reaction 3:
**Reactants:**
- 4-Amino-2-hydroxybenzoic acid (salicylamide).
- An excessive amount of acetic anhydride.
- Water.

**Instructions:**
1. React salicylamide with an excessive amount of acetic anhydride.
2. Add water to the reaction mixture.

**Expected Product:**
- The stable organic product will be an acetylated amide and ester. The hydroxyl and amino groups will react with acetic anhydride to form acetate esters.

#### Reaction 4:
**Reactants:**
- A five-membered cyclic imide.
- 1 equivalent of a diamine (pyrrolidine-2,5-diamine).
- Water/HCl (Hydrochloric acid aqueous solution).

**Instructions:**
1. Combine the cyclic imide with the diamine in equimolar amounts.
2. Follow the reaction with the addition of water and hydrochloric acid.

**Expected Product:**
- The stable organic product will be a ring-opened

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