Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The image consists of a chemical reaction and several potential products. The reaction involves a starting compound with two ketone groups and an excess of sodium borohydride (NaBH₄) in methanol (CH₃OH), which acts as a reducing agent. The reaction aims to reduce the ketone groups to alcohol groups.
Below the reaction, there are five possible products, labeled I through V:
1. **Compound I**: Displays a single secondary alcohol at one of the originally ketone positions.
2. **Compound II**: Maintains one ketone functional group and reduces the other ketone group to a secondary alcohol.
3. **Compound III**: Reduces both ketone groups to secondary alcohols.
4. **Compound IV**: Displays reduction at one ketone position to form a secondary alcohol, but not at the other ketone position.
5. **Compound V**: Transforms both ketone groups into tertiary alcohols.
A multiple-choice question is presented beneath the structural formulas, asking which compound correctly represents the product of the reaction.
**Options:**
- O II
- O III (This option is marked with a blue dot, indicating it is selected)
- O I
- O IV
- O V
**Explanation of Reaction and Choice:**
In the presence of excess NaBH₄ in methanol, both ketone groups are expected to be reduced to alcohol groups. The correct product should, therefore, be Compound III, where both ketone groups are converted to secondary alcohols.
Understanding the mechanisms of functional group reduction and the role of different reducing agents is crucial in organic chemistry synthesis and analysis. This reaction highlights the application of NaBH₄, a common reducing agent, in converting ketones to alcohols, a fundamental transformation in synthetic organic chemistry.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1d27d76a-97fc-4fcb-a4e1-0da9ccc7855c%2F48adf88c-87e2-4610-abfc-7fa73934eeaa%2Fopomhwj0b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Predict the product for the following reaction:**
The image consists of a chemical reaction and several potential products. The reaction involves a starting compound with two ketone groups and an excess of sodium borohydride (NaBH₄) in methanol (CH₃OH), which acts as a reducing agent. The reaction aims to reduce the ketone groups to alcohol groups.
Below the reaction, there are five possible products, labeled I through V:
1. **Compound I**: Displays a single secondary alcohol at one of the originally ketone positions.
2. **Compound II**: Maintains one ketone functional group and reduces the other ketone group to a secondary alcohol.
3. **Compound III**: Reduces both ketone groups to secondary alcohols.
4. **Compound IV**: Displays reduction at one ketone position to form a secondary alcohol, but not at the other ketone position.
5. **Compound V**: Transforms both ketone groups into tertiary alcohols.
A multiple-choice question is presented beneath the structural formulas, asking which compound correctly represents the product of the reaction.
**Options:**
- O II
- O III (This option is marked with a blue dot, indicating it is selected)
- O I
- O IV
- O V
**Explanation of Reaction and Choice:**
In the presence of excess NaBH₄ in methanol, both ketone groups are expected to be reduced to alcohol groups. The correct product should, therefore, be Compound III, where both ketone groups are converted to secondary alcohols.
Understanding the mechanisms of functional group reduction and the role of different reducing agents is crucial in organic chemistry synthesis and analysis. This reaction highlights the application of NaBH₄, a common reducing agent, in converting ketones to alcohols, a fundamental transformation in synthetic organic chemistry.
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