Predict the pressure that would be observed if the container was at a temperature of 1,135K Graph of Pressurev/s Temperature18y= 0.017x+ 1.940161412Scale: On x-axis, 1 cm=200K10On y axis, 1 cm=2 atm842004006008001000Temperature (K)Pressure (atm) 1. In an experiment, a closed container holds a 10.0 g sample of an alcohol. Thecontainer is cooled at a constant rate. The sample's temperature is recorded eachminute. A graph of the data is below. A phase diagram for the alcohol is alsoshown.COOLING CURVE FOR ANPHASE DIAGRAM OF AN ALCOHOLALCOHOLy62500liquidsolid4001.003002004.2 x 10-9100gas0-1015Time (min)150 159351 514Temperature (K) (not to scale)Temperature (K)20Pressure (atm) (not to scale)

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Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Predict the pressure that would be observed if the container was at a temperature of 1,135K

Graph of Pressurev/s Temperature
18
y= 0.017x+ 1.940
16
14
12
Scale: On x-axis, 1 cm=200K
10
On y axis, 1 cm=2 atm
8
4
200
400
600
800
1000
Temperature (K)
Pressure (atm)

1. In an experiment, a closed container holds a 10.0 g sample of an alcohol. The
container is cooled at a constant rate. The sample's temperature is recorded each
minute. A graph of the data is below. A phase diagram for the alcohol is also
shown.
COOLING CURVE FOR AN
PHASE DIAGRAM OF AN ALCOHOL
ALCOHOL
y
62
500
liquid
solid
400
1.00
300
200
4.2 x 10-9
100
gas
0-
10
15
Time (min)
150 159
351 514
Temperature (K) (not to scale)
Temperature (K)
20
Pressure (atm) (not to scale)

Expert Solution

Step 1

In this question, we have a pressure vs temperature graph where Pressure is plotted on the Y-axis(dependent variable) and Temperature is plotted on the X-axis(independent variable).

Regression equation for the straight line is given as:

y = 0.017x + 1.940

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