Predict the multiplicity of each of the signals you would expect to see in the ‘H NMR, spectrum of the compound below label each unique ‘H with s, d, t, q, or m. Explain

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Predict the multiplicity of each of the signals you would expect to see in the ‘H NMR, spectrum of the compound below label each unique ‘H with s, d, t, q, or m. Explain
The image depicts the chemical structure of an organic compound. 

### Structural Details:
- **Benzene Ring**: At the center of the structure is a six-membered benzene ring, indicated by the alternating single and double bonds within the hexagon.
- **Substituents**:
  - **Chlorine (Cl)**: Attached to the ring is a chlorine atom, located at the upper left side, connected by a single bond.
  - **Propyl Group**: Extending from the chlorine is an ethyl group, forming the top right substituent.
  - **Acetate Group**: At the lower part of the benzene ring, a structure resembling an acetate group is present. This consists of:
    - A carbonyl group (C=O).
    - A single bond connecting to an -OCH3 (methoxy) group.

The structure is indicative of an aromatic compound with chlorine and acetate functionalities, which influences its chemical properties and potential reactivity.
Transcribed Image Text:The image depicts the chemical structure of an organic compound. ### Structural Details: - **Benzene Ring**: At the center of the structure is a six-membered benzene ring, indicated by the alternating single and double bonds within the hexagon. - **Substituents**: - **Chlorine (Cl)**: Attached to the ring is a chlorine atom, located at the upper left side, connected by a single bond. - **Propyl Group**: Extending from the chlorine is an ethyl group, forming the top right substituent. - **Acetate Group**: At the lower part of the benzene ring, a structure resembling an acetate group is present. This consists of: - A carbonyl group (C=O). - A single bond connecting to an -OCH3 (methoxy) group. The structure is indicative of an aromatic compound with chlorine and acetate functionalities, which influences its chemical properties and potential reactivity.
Expert Solution
Step 1

The splitting of nmr signals follows (n+1) rule. here, n = the no. of adjacent hydrogens.

if,

n =0,

0+1=1, singlet,

n =1,

1+1=2, doublet,

n = 2,

2+1=3, triplet,

n =3,

3+1=4, quartet,

n =4,

4+1=5, quintet,

etc..

 

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