Practice/Exercises: Solve the following problems. 1. A normal distribution of scores has a mean of 120 and a standard deviation of 20. What score separates the top 40% of the scores from the rest?
Practice/Exercises: Solve the following problems. 1. A normal distribution of scores has a mean of 120 and a standard deviation of 20. What score separates the top 40% of the scores from the rest?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Please answer the exercise and sketch the normal curve
![b. Step 1. Convert the score 38 to z-score
Z=
X-X
S
=
38 - 45
4
Z = -1.75
Step 2. Sketch the normal curve.
-1.75
38
Let A = area below z = -1.75
A₁ = area between z = 0 and z = -1.75
A₂ = area of half the curve
From the table,
A₁ = 0.4599
A = A₂ - A₁
= 0.5-0.4599
A = 0.0401
The probability that a score picked up at random will lie below 38 is 0.0401.
Practice/Exercises: Solve the following problems.
1. A normal distribution of scores has a mean of 120 and a standard deviation of 20. What score
separates the top 40% of the scores from the rest?
A2
A1
0
45](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8139ab6e-acce-439f-a4b4-e735c58bc964%2Ff97af4b9-9641-4441-b7d3-95d27aea9523%2Fpwd147_processed.jpeg&w=3840&q=75)
Transcribed Image Text:b. Step 1. Convert the score 38 to z-score
Z=
X-X
S
=
38 - 45
4
Z = -1.75
Step 2. Sketch the normal curve.
-1.75
38
Let A = area below z = -1.75
A₁ = area between z = 0 and z = -1.75
A₂ = area of half the curve
From the table,
A₁ = 0.4599
A = A₂ - A₁
= 0.5-0.4599
A = 0.0401
The probability that a score picked up at random will lie below 38 is 0.0401.
Practice/Exercises: Solve the following problems.
1. A normal distribution of scores has a mean of 120 and a standard deviation of 20. What score
separates the top 40% of the scores from the rest?
A2
A1
0
45
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