The solution is the way to node Practice:Using nodal analysis, find Vi and v2 in the circuit of the below figure.0.2 F16.14.V2VIww10 sin 21 A3V,vi(t) = 20.96 sin(2t +58°) V, v2(1) = 44.11 sin(2t+41°) V.Solution:Thi-Qar University/Department of Electrical and Electronic Engineering-Lectures are prepared by M.Sc. Al KareemPage 2

Nodal Analysis - It is used to find node voltage using Kirchhoff's current law. Kirchhoff's current…

Answered: Practice: Using nodal analysis, find Vi…

Practice: Using nodal analysis, find Vi and v2 in the circuit of the below figure. 0.2 F 16.1 V2 ww- 10 sin 21 A 3v vi (t) = 20.96 sin(2t + 58°) V, vz(1) = 44.11 sin(21 + 41°) V. Solution: %3D %3D

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter24: Resistive-inductive-capacitive Parallel Circuits

Section: Chapter Questions

Problem 1RQ: An AC circuit contains a 24 resistor, a 15.9-mH inductor, and a 13.3F capacitor connected in...

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

The solution is the way to node

Practice:
Using nodal analysis, find Vi and v2 in the circuit of the below figure.
0.2 F
16.1
4.
V2
VI
ww
10 sin 21 A
3V,
vi(t) = 20.96 sin(2t +58°) V, v2(1) = 44.11 sin(2t+41°) V.
Solution:
Thi-Qar University/Department of Electrical and Electronic Engineering-Lectures are prepared by M.Sc. Al Kareem
Page 2

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