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PRACTICE IT Use the worked example above to help you solve this problem. A train at a speed of 36.4 m/s sounds it whistle, which has a frequency of 5.06 x 102 Hz. Determine the frequency heard by a stationary observer s.the.train.approaches the observer. The ambient temperature is 21.7°C.

PRACTICE IT Use the worked example above to help you solve this problem. A train at a speed of 36.4 m/s sounds it whistle, which has a frequency of 5.06 x 102 Hz. Determine the frequency heard by a stationary observer s.the.train.approaches the observer. The ambient temperature is 21.7°C.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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LEARN MORE REMARKS If the train were going away from the observer, vs = -40.0 m/s would have been chosen instead. QUESTION Does the Doppler shift change due to temperature variations? If so, why? For typical daily variations in temperature in a moderate climate, would any change in the Doppler shift be best characterized as nonexistent, small, or large? No. Temperature does not enter into the calculation of the Doppler shift. Yes. A change in temperature changes the speed of sound and the Doppler shift, causing changes of a few percent. Yes. A change in temperature changes the speed of sound and the Doppler shift, but only insignificantly. Yes. A change in temperature changes the speed of sound and the Doppler shift, easily doubling or tripling the size of the shift. PRACTICE IT Use the worked example above to help you solve this problem. A train at a speed of 36.4 m/s sounds it whistle, which has a frequency of 5.06 x 10² Hz. Determine the frequency heard by a stationary observer as the train approaches the observer. The ambient temperature is 21.7°C. Enter a number. differs from the correct answer by more than 10%. Double check your calculations. Hz
Transcribed Image Text:LEARN MORE REMARKS If the train were going away from the observer, vs = -40.0 m/s would have been chosen instead. QUESTION Does the Doppler shift change due to temperature variations? If so, why? For typical daily variations in temperature in a moderate climate, would any change in the Doppler shift be best characterized as nonexistent, small, or large? No. Temperature does not enter into the calculation of the Doppler shift. Yes. A change in temperature changes the speed of sound and the Doppler shift, causing changes of a few percent. Yes. A change in temperature changes the speed of sound and the Doppler shift, but only insignificantly. Yes. A change in temperature changes the speed of sound and the Doppler shift, easily doubling or tripling the size of the shift. PRACTICE IT Use the worked example above to help you solve this problem. A train at a speed of 36.4 m/s sounds it whistle, which has a frequency of 5.06 x 10² Hz. Determine the frequency heard by a stationary observer as the train approaches the observer. The ambient temperature is 21.7°C. Enter a number. differs from the correct answer by more than 10%. Double check your calculations. Hz
EXAMPLE 14.4 GOAL Solve a Doppler shift problem when only the source is moving. Listen, but Don't Stand on the Track PROBLEM A train moving at a speed of 40.0 m/s sounds its whistle, which has a frequency of 5.00 x 10² Hz. Determine the frequency heard by a stationary observer as the train approaches the observer. The ambient temperature is 24.0°C. STRATEGY Get the speed of sound at the ambient temperature using the relevant equation, then substitute values into the Doppler shift equation. Because the train approaches the observer, the observed frequency will be larger. Choose the sign of vs to reflect this fact. SOLUTION Calculate the speed of sound in air at T = 24.0°C. The observer is stationary, so vo = 0. The train is moving toward the observer, so vs = 40.0 m/s (positive). Substitute these values and the speed of sound into the Doppler shift equation. v = (331 m/s) √T/ 273 K (331 m/s) √(273 + 24.0) K/ 273 K = = fo=fs ( v + vo V - VS = 566 Hz = (5.00 x 10² Hz) 345 m/s 345 m/s 345 m/s - 40.0 m/s
Transcribed Image Text:EXAMPLE 14.4 GOAL Solve a Doppler shift problem when only the source is moving. Listen, but Don't Stand on the Track PROBLEM A train moving at a speed of 40.0 m/s sounds its whistle, which has a frequency of 5.00 x 10² Hz. Determine the frequency heard by a stationary observer as the train approaches the observer. The ambient temperature is 24.0°C. STRATEGY Get the speed of sound at the ambient temperature using the relevant equation, then substitute values into the Doppler shift equation. Because the train approaches the observer, the observed frequency will be larger. Choose the sign of vs to reflect this fact. SOLUTION Calculate the speed of sound in air at T = 24.0°C. The observer is stationary, so vo = 0. The train is moving toward the observer, so vs = 40.0 m/s (positive). Substitute these values and the speed of sound into the Doppler shift equation. v = (331 m/s) √T/ 273 K (331 m/s) √(273 + 24.0) K/ 273 K = = fo=fs ( v + vo V - VS = 566 Hz = (5.00 x 10² Hz) 345 m/s 345 m/s 345 m/s - 40.0 m/s
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