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Practice: Determine the Norton equivalent of the circuit in the figure below as seen from terminals 16.10 a-b. Use the equivalent to find lo. 4 j2 ell -13 10 20/0° V 4/-90° A Answer: ZN 3.176+j0.706 2, IN =8.396/-32.68° A, L = 1.971/-2.101° A. %3D %3D %3D

Practice: Determine the Norton equivalent of the circuit in the figure below as seen from terminals 16.10 a-b. Use the equivalent to find lo. 4 j2 ell -13 10 20/0° V 4/-90° A Answer: ZN 3.176+j0.706 2, IN =8.396/-32.68° A, L = 1.971/-2.101° A. %3D %3D %3D

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Practice: Determine the Norton equivalent of the circuit in the figure below as seen from terminals a-b. Use the equivalent to find lo. 16.10 4 ww j2 ell -13 8 ww ww 10 20/0° V ) 4/-90° A --j5 Answer: ZN = 3.176 + j0.706 2, IN = 8.396/- 32.68 A, I, = 1.971, 2.101° A.
Transcribed Image Text:Practice: Determine the Norton equivalent of the circuit in the figure below as seen from terminals a-b. Use the equivalent to find lo. 16.10 4 ww j2 ell -13 8 ww ww 10 20/0° V ) 4/-90° A --j5 Answer: ZN = 3.176 + j0.706 2, IN = 8.396/- 32.68 A, I, = 1.971, 2.101° A.
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