Practice 1. Use the sine ratio, the cosecant ratio, or the inverse sine to solve for x. Round each answer to the nearest tenth. a. F 57° X 11 ft M b. P 17 yd 25 yd S C C. C 15 m 2√2 m
Practice 1. Use the sine ratio, the cosecant ratio, or the inverse sine to solve for x. Round each answer to the nearest tenth. a. F 57° X 11 ft M b. P 17 yd 25 yd S C C. C 15 m 2√2 m
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Question

Transcribed Image Text:Draw and label right triangle PQR
with LQ = 90°. Then describe the
sine ratio in terms of ZR and ZP.
Practice
1. Use the sine ratio, the cosecant ratio, or the inverse sine to solve for x. Round each answer to the
nearest tenth.
a.
57°
X
Y
11 ft
M
The sine of an acute angle in a right triangle is the ratio of the
length of the side that is opposite the angle to the length of
the hypotenuse. The cosecant of an acute angle is the inverse
of the sine of the same angle. The inverse sine of x, or sin-¹
x, can be used to determine the measure of an acute angle
whose sine is x.
b.
d. Determine length BG of the
support beam.
2. Consider the roof truss shown. Round each
answer to the nearest hundredth.
17 yd
25 yd
a. Determine the height CG of the roof truss.
b. Determine length AB.
c. Determine the measure of LBGC.
40°
X
S
16 ft B
6 ft
H
DG
G
C. C
D
F
X
15 m
2√2 m
20
E
LESSON 3: The Sine Ratio M3-1
•
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