PQ-8. What is the major product of this reaction? (A) (B)

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**Title: Understanding Reaction Products in Organic Chemistry**

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**Problem Statement:**

**PQ-8.** What is the major product of this reaction?

**Reaction Details:**

The reaction involves an alkyl bromide compound reacting with sodium ethoxide (CH₃CH₂ONa) in ethanol (CH₃CH₂OH). The structure of the starting compound shows a bromine atom attached to a secondary carbon.

**Options for the Major Product:**

- **(A)** Structure: A carbon chain with a double bond between the first and second carbons.

- **(B)** Structure: A carbon chain with a double bond between the second and third carbons.

- **(C)** Structure: A carbon chain with a stereocenter and a double bond further along the chain.

- **(D)** Structure: A branched carbon chain with a double bond at the branch.

**Mechanism Explanation:**

The reaction follows an elimination mechanism (likely E2 due to the presence of a strong base and a secondary substrate). The leaving group (Br) is removed, and a double bond is formed.

**Key Points:**

- Consider Zaitsev's rule which suggests that the more substituted alkene (double bond between more highly substituted carbons) will be the major product due to its greater stability.

- Analyze the positions of possible double bonds and the stability offered by these configurations. 

**Conclusion:**

Based on common elimination reaction principles, predict which structure (A, B, C, or D) is the likely major product of this reaction. This would involve assessing which product is more thermodynamically stable due to higher substitution around the formed double bond.

**Note:** Always verify prediction with proper analysis or experimental evidence where possible.

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Transcribed Image Text:**Title: Understanding Reaction Products in Organic Chemistry** --- **Problem Statement:** **PQ-8.** What is the major product of this reaction? **Reaction Details:** The reaction involves an alkyl bromide compound reacting with sodium ethoxide (CH₃CH₂ONa) in ethanol (CH₃CH₂OH). The structure of the starting compound shows a bromine atom attached to a secondary carbon. **Options for the Major Product:** - **(A)** Structure: A carbon chain with a double bond between the first and second carbons. - **(B)** Structure: A carbon chain with a double bond between the second and third carbons. - **(C)** Structure: A carbon chain with a stereocenter and a double bond further along the chain. - **(D)** Structure: A branched carbon chain with a double bond at the branch. **Mechanism Explanation:** The reaction follows an elimination mechanism (likely E2 due to the presence of a strong base and a secondary substrate). The leaving group (Br) is removed, and a double bond is formed. **Key Points:** - Consider Zaitsev's rule which suggests that the more substituted alkene (double bond between more highly substituted carbons) will be the major product due to its greater stability. - Analyze the positions of possible double bonds and the stability offered by these configurations. **Conclusion:** Based on common elimination reaction principles, predict which structure (A, B, C, or D) is the likely major product of this reaction. This would involve assessing which product is more thermodynamically stable due to higher substitution around the formed double bond. **Note:** Always verify prediction with proper analysis or experimental evidence where possible. ---
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