PPP.21 o Jn 00.2 22) What are the respective concentrations (M) of Cu2+ and Cl- afforded by dissolving 0.592 mol 22) CuCl2 in water and diluting to 258 mL? A) D.00229 and 2.29 B) 2.29 and 2.29 0.436 and 0.0764 AD) 2.29 and 4.59 E)0.00229 and 0.00229 M= mol 0. S92 Cu 2t +C 2. 0.258 M,VI = M2 VQ %3D (2057xt07253tEH) TtO ా

Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I know the answer is D and we'll use the M1V1=M2V2 formula.

PPP.21
o Jn 00.2
22) What are the respective concentrations (M) of Cu2+ and Cl- afforded by dissolving 0.592 mol
22)
CuCl2 in water and diluting to 258 mL?
A) D.00229 and 2.29
B) 2.29 and 2.29
0.436 and 0.0764
AD) 2.29 and 4.59
E)0.00229 and 0.00229
M= mol
0. S92
Cu
2t +C
2.
0.258
M,VI
= M2 VQ
%3D
(2057xt07253tEH)
TtO ా
Transcribed Image Text:PPP.21 o Jn 00.2 22) What are the respective concentrations (M) of Cu2+ and Cl- afforded by dissolving 0.592 mol 22) CuCl2 in water and diluting to 258 mL? A) D.00229 and 2.29 B) 2.29 and 2.29 0.436 and 0.0764 AD) 2.29 and 4.59 E)0.00229 and 0.00229 M= mol 0. S92 Cu 2t +C 2. 0.258 M,VI = M2 VQ %3D (2057xt07253tEH) TtO ా
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