PPP.21 o Jn 00.2 22) What are the respective concentrations (M) of Cu2+ and Cl- afforded by dissolving 0.592 mol 22) CuCl2 in water and diluting to 258 mL? A) D.00229 and 2.29 B) 2.29 and 2.29 0.436 and 0.0764 AD) 2.29 and 4.59 E)0.00229 and 0.00229 M= mol 0. S92 Cu 2t +C 2. 0.258 M,VI = M2 VQ %3D (2057xt07253tEH) TtO ా
PPP.21 o Jn 00.2 22) What are the respective concentrations (M) of Cu2+ and Cl- afforded by dissolving 0.592 mol 22) CuCl2 in water and diluting to 258 mL? A) D.00229 and 2.29 B) 2.29 and 2.29 0.436 and 0.0764 AD) 2.29 and 4.59 E)0.00229 and 0.00229 M= mol 0. S92 Cu 2t +C 2. 0.258 M,VI = M2 VQ %3D (2057xt07253tEH) TtO ా
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I know the answer is D and we'll use the M1V1=M2V2 formula.

Transcribed Image Text:PPP.21
o Jn 00.2
22) What are the respective concentrations (M) of Cu2+ and Cl- afforded by dissolving 0.592 mol
22)
CuCl2 in water and diluting to 258 mL?
A) D.00229 and 2.29
B) 2.29 and 2.29
0.436 and 0.0764
AD) 2.29 and 4.59
E)0.00229 and 0.00229
M= mol
0. S92
Cu
2t +C
2.
0.258
M,VI
= M2 VQ
%3D
(2057xt07253tEH)
TtO ా
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