Power series expansions can also be very useful for calculating indeterminate forms. Just for fun, try to calculate the indeterminate forms sin(x) lim et and lim x→0 - x 1 x2 using our power series representation of sin(x) and e". sin(x) = > (-1)"x2n+1 (2n + 1)! x' +. 7! 3! 5! n=0 x2 = 1+ x + 2! x4 + 4! ... n! 3! + + ||
Power series expansions can also be very useful for calculating indeterminate forms. Just for fun, try to calculate the indeterminate forms sin(x) lim et and lim x→0 - x 1 x2 using our power series representation of sin(x) and e". sin(x) = > (-1)"x2n+1 (2n + 1)! x' +. 7! 3! 5! n=0 x2 = 1+ x + 2! x4 + 4! ... n! 3! + + ||
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Power series expansions can also be very useful for calculating indeterminate forms.
Just for fun, try to calculate the indeterminate forms
sin(x)
lim
et – x
1
-
and lim
x2
using our power series representation of sin(x) and e".
Σ
(-1)"x²n+1
(2n + 1)!
x7
+
7!
sin(x)
= X
-
-
3!
5!
n=0
4
x"
= 1+x +
n!
n=0
et
+
4!
%3D
..
2!
3!](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1e11185d-5319-4a73-bbe9-1522ef121b33%2Fa56c0937-a237-4921-9231-2fe75cfa6f7a%2F6gh5dwe_processed.png&w=3840&q=75)
Transcribed Image Text:Power series expansions can also be very useful for calculating indeterminate forms.
Just for fun, try to calculate the indeterminate forms
sin(x)
lim
et – x
1
-
and lim
x2
using our power series representation of sin(x) and e".
Σ
(-1)"x²n+1
(2n + 1)!
x7
+
7!
sin(x)
= X
-
-
3!
5!
n=0
4
x"
= 1+x +
n!
n=0
et
+
4!
%3D
..
2!
3!
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