POWAH! UNLIMITED POWAH! Problem Emperor Palpatine has the vicious ability to shoot force lightning out of his fingers. The way this works is actually quite predictable through some mathematical computation. Depending on how much Palpatine has exerted himself that day, he has a certain amount of energy E stored. Once he starts shooting lightning, the power P of his lightning is equal to 1. After each millisecond, Pincreases by a factor of E that is to say, we multiply P by E to get the new P. Given Palpatine's initial energy E and the number of milliseconds he has been shooting lightning out of his fingers, compute the power P of his lightning. Since this may be very large, output P modulo 107. 24 Input Format Input consists of a single test case containing a line with two integers E and T separated by a space indicating the energy and the time elapsed in milliseconds. Constraints 1≤E≤ 10¹2 0≤T≤ 10¹2 Output Format Output consists of one line containing Palpatine's power P after T milliseconds modulo 107. Sample Input 0 Sample Output 0 16 Sample Input 1 Submissions 10 4 Discussions Sample Output 1 10000

POWAH! UNLIMITED POWAH! Problem Emperor Palpatine has the vicious ability to shoot force lightning out of his fingers. The way this works is actually quite predictable through some mathematical computation. Depending on how much Palpatine has exerted himself that day, he has a certain amount of energy E stored. Once he starts shooting lightning, the power P of his lightning is equal to 1. After each millisecond, Pincreases by a factor of E that is to say, we multiply P by E to get the new P. Given Palpatine's initial energy E and the number of milliseconds he has been shooting lightning out of his fingers, compute the power P of his lightning. Since this may be very large, output P modulo 107. 24 Input Format Input consists of a single test case containing a line with two integers E and T separated by a space indicating the energy and the time elapsed in milliseconds. Constraints 1≤E≤ 10¹2 0≤T≤ 10¹2 Output Format Output consists of one line containing Palpatine's power P after T milliseconds modulo 107. Sample Input 0 Sample Output 0 16 Sample Input 1 Submissions 10 4 Discussions Sample Output 1 10000

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

PUP Problem Set

Can be answered in Java 8, C++14, or Pypy 3

POWAH! UNLIMITED POWAH!
Problem
Emperor Palpatine has the vicious ability to shoot force lightning out of his fingers. The way this works is
actually quite predictable through some mathematical computation. Depending on how much Palpatine has
exerted himself that day, he has a certain amount of energy E stored. Once he starts shooting lightning, the
power P of his lightning is equal to 1. After each millisecond, P increases by a factor of E that is to say, we
multiply P by E to get the new P.
Given Palpatine's initial energy E and the number of milliseconds he has been shooting lightning out of his
fingers, compute the power P of his lightning. Since this may be very large, output P modulo 107.
24
Input Format
Input consists of a single test case containing a line with two integers E and T separated by a space indicating
the energy and the time elapsed in milliseconds.
Constraints
1≤E≤ 10¹2
0≤T≤ 10¹2
Output Format
Output consists of one line containing Palpatine's power P after T milliseconds modulo 107.
Sample Input 0
Sample Output 0
16
Sample Input 1
Submissions
10 4
Discussions
Sample Output 1
10000

1 import java.io. Buffered Reader;
2 import java.io.InputStreamReader;
3
Nm tibro ao-NM +
4 public class Solution {
5-
6
7
8.
9-
10
11
12
13
14
15
16
17 }
public static void main(String[] args) throws Exception {
Buffered Reader br = new Buffered Reader (new InputStreamReader (System.in));
String[] parts = br.readLine().trim().split(" ");
}
long e = Long.parse Long (parts[0]);
long t = Long.parseLong (parts [1]);
// compute for answer
public static long solve (long e, long t) {
}

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