Potassium iodate solution was prepared by dissolving 1.022 g of KIO3 (214.00 g/mol) in a 500-mL volumetric flask. Then 50.00 mL of the solution were pipetted into a flask and treated with excess KI and acid (H2SO4), liberating triiodide, I. 103- + 81-+ 6H 313- + 3H20 How many moles of I3 are created by the reaction in the treated aliquot? a) 0.0002865 mol b) 0.001433 mol c) 0.09551 mol d) 0.3333 mol e) 3.000 mol The 50-mL solution above was then used to standardize sodium thiosulfate, Na2S203 where titration required 37.66 mL. What is the concentration of the Na2S2O3 solution? 13 + 2S2032- = 31- + S,06?- a) 0.01902 M b) 0.02168 M c) 0.05731 M d) 0.07609 M e) 0.1141 M

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Potassium iodate solution was prepared by dissolving 1.022 g of KIO3 (214.00 g/mol) in a 500-mL
volumetric flask. Then 50.00 mL of the solution were pipetted into a flask and treated with excess KI
and acid (H2SO4), liberating triiodide, I.
103- + 81-+ 6H = 313- + 3H2O
How many moles of I3 are created by the reaction in the treated aliquot?
a) 0.0002865 mol
b) 0.001433 mol
c) 0.09551 mol
d) 0.3333 mol
e) 3.000 mol
The 50-mL solution above was then used to standardize sodium thiosulfate, NazS2O3 where titration
required 37.66 mL. What is the concentration of the Na2S2O3 solution?
13- + 2S,032- 31- + S,062-
a) 0.01902 M
b) 0.02168 M
c) 0.05731 M
d) 0.07609M
e) 0.1141 M
Transcribed Image Text:Potassium iodate solution was prepared by dissolving 1.022 g of KIO3 (214.00 g/mol) in a 500-mL volumetric flask. Then 50.00 mL of the solution were pipetted into a flask and treated with excess KI and acid (H2SO4), liberating triiodide, I. 103- + 81-+ 6H = 313- + 3H2O How many moles of I3 are created by the reaction in the treated aliquot? a) 0.0002865 mol b) 0.001433 mol c) 0.09551 mol d) 0.3333 mol e) 3.000 mol The 50-mL solution above was then used to standardize sodium thiosulfate, NazS2O3 where titration required 37.66 mL. What is the concentration of the Na2S2O3 solution? 13- + 2S,032- 31- + S,062- a) 0.01902 M b) 0.02168 M c) 0.05731 M d) 0.07609M e) 0.1141 M
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