Potassium iodate, KIO3, was prepared by dissolving 2.023 g of KIO3 in a 500 mL volumetric flask. A 50 mL aliquot of the solution was treated in excess 1 g Kl and 15 mL of 0.5033 molar H₂SO4. a. Calculate the mmoles of 13 created on the reaction? Reaction: 103 + 1 → 13 + H₂O b. The triiodide formed reacted with 38.66 mL of standard Na2S2O3 solution. Calculate the concentration of the standard solution? Reaction: 13 + S2O3-2 → |- + S406-²
Potassium iodate, KIO3, was prepared by dissolving 2.023 g of KIO3 in a 500 mL volumetric flask. A 50 mL aliquot of the solution was treated in excess 1 g Kl and 15 mL of 0.5033 molar H₂SO4. a. Calculate the mmoles of 13 created on the reaction? Reaction: 103 + 1 → 13 + H₂O b. The triiodide formed reacted with 38.66 mL of standard Na2S2O3 solution. Calculate the concentration of the standard solution? Reaction: 13 + S2O3-2 → |- + S406-²
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
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Chapter15: Solutions
Section: Chapter Questions
Problem 87QAP: 87. What volume of 0.151 N NaOH is required to neutralize 24.2 mL of 0.125 N H2SO4? What volume of...
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Please round off all answer to 4 decimal places thank u

Transcribed Image Text:Potassium iodate, KIO3, was prepared by dissolving 2.023 g of KIO3 in a 500 mL volumetric
flask. A 50 mL aliquot of the solution was treated in excess 1 g Kl and 15 mL of 0.5033 molar
H₂SO4.
a. Calculate the mmoles of 13 created on the reaction?
Reaction: 103 + 1 → 13 + H₂O
b. The triiodide formed reacted with 38.66 mL of standard Na2S2O3 solution. Calculate
the concentration of the standard solution?
Reaction:
13 + S2O3-2 → |- + S406-²
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