Potassium hypobromite, KOBr, converts ammonia to nitrogen by the following reaction. 3KOBr +2NH3 yields N2 + 3KBr + 3H20 To prepare 461.1 ml of dry N2, when measured at 24.5 degrees Celsius and 756.3 torr, what is the minimum number of grams of KOBr required?
Potassium hypobromite, KOBr, converts ammonia to nitrogen by the following reaction. 3KOBr +2NH3 yields N2 + 3KBr + 3H20 To prepare 461.1 ml of dry N2, when measured at 24.5 degrees Celsius and 756.3 torr, what is the minimum number of grams of KOBr required?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Potassium hypobromite, KOBr, converts ammonia to nitrogen by the following reaction.
3KOBr +2NH3 yields N2 + 3KBr + 3H20
To prepare 461.1 ml of dry N2, when measured at 24.5 degrees Celsius and 756.3 torr, what is the minimum number of grams of KOBr required?
Expert Solution
Step 1
To determine the minimum number of grams of KOBr required to produce 461.1 ml of dry N2 gas at 24.5 degrees Celsius and 756.3 torr, we need to use the ideal gas law and stoichiometry.
First, we need to convert the volume of N2 to moles using the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
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