postfix notation is an unambiguous way of writing an arithmetic expression without parentheses. It is defined so that if “(exp₁) op (exp₂)” is a normal (infix) fully parenthesized expression with opera- tion op, then its postfix equivalent is “pexp₁ pexp2 op”, where pexp₁ is the postfix version of exp₁ and pexp is the postfix version of exp2. The postfix version of a single number or variable is just that number or variable. So, for example, the postfix version of the infix expression “((5+2) ⋆ (8 − 3))/4” is “5 2 + 8 3 − * 4 /". Give an efficient algorithm for converting an infix arithmetic expression to its equivalent postfix notation. (Hint: First convert the infix expression into its equivalent binary tree representation.) examples: Infix: ((5+2)*(8−3))/4 Postfix: 52 +8 3 − * 4 / Infix: 2*20/2+(3+4)*3^2-6+15 Postfix: 2 20 * 2 / 34+32^*+ 6 - 15 +

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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postfix notation is an unambiguous way of
writing an arithmetic expression without parentheses. It is defined so that if
"(exp₁) op (exp₂)” is a normal (infix) fully parenthesized expression with opera-
tion op, then its postfix equivalent is “pexp₁ pexp₂ op", where pexp₁ is the postfix
version of exp₁ and pexp2 is the postfix version of exp2. The postfix version of
a single number or variable is just that number or variable. So, for example, the
postfix version of the infix expression “((5+2) * (8 − 3))/4” is “5 2 + 8 3 − *
4 /". Give an efficient algorithm for converting an infix arithmetic expression to
its equivalent postfix notation. (Hint: First convert the infix expression into its
equivalent binary tree representation.)
examples:
Infix: ((5+2)*(8−3))/4
Postfix: 52 + 83-* 4/
Infix: 2*20/2+(3+4)*3^2-6+15
Postfix: 2 20*2/34+32^*+6-15+
Transcribed Image Text:postfix notation is an unambiguous way of writing an arithmetic expression without parentheses. It is defined so that if "(exp₁) op (exp₂)” is a normal (infix) fully parenthesized expression with opera- tion op, then its postfix equivalent is “pexp₁ pexp₂ op", where pexp₁ is the postfix version of exp₁ and pexp2 is the postfix version of exp2. The postfix version of a single number or variable is just that number or variable. So, for example, the postfix version of the infix expression “((5+2) * (8 − 3))/4” is “5 2 + 8 3 − * 4 /". Give an efficient algorithm for converting an infix arithmetic expression to its equivalent postfix notation. (Hint: First convert the infix expression into its equivalent binary tree representation.) examples: Infix: ((5+2)*(8−3))/4 Postfix: 52 + 83-* 4/ Infix: 2*20/2+(3+4)*3^2-6+15 Postfix: 2 20*2/34+32^*+6-15+
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