Point charges qA = 6.0 nC is located at (2.00 m, 0) and qB = -2.5 nC is located at (0, 3.00 m). What is the electric potential at point P (0, 0), in Volts? 1.00 nC = 1.00 x 109 C. Use K = 9.00 × 10⁹ Nm²/c².
Point charges qA = 6.0 nC is located at (2.00 m, 0) and qB = -2.5 nC is located at (0, 3.00 m). What is the electric potential at point P (0, 0), in Volts? 1.00 nC = 1.00 x 109 C. Use K = 9.00 × 10⁹ Nm²/c².
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:**Problem Statement**
Consider the point charges \( q_A = 6.0 \, \text{nC} \) and \( q_B = -2.5 \, \text{nC} \). Charge \( q_A \) is located at coordinates \( (2.00 \, \text{m}, 0) \) and charge \( q_B \) is located at \( (0, 3.00 \, \text{m}) \). Calculate the electric potential at point \( P (0, 0) \), expressed in Volts. Note that \( 1.00 \, \text{nC} = 1.00 \times 10^{-9} \, \text{C} \) and use the constant \( K = 9.00 \times 10^9 \, \text{N} \cdot \text{m}^2/\text{C}^2 \).
**Details for Educational Context**
This problem requires an understanding of concepts such as electric charges, potential, and the use of Coulomb’s law to find the electric potential at a given point. The charges are in nanocoulombs (nC), and the conversion to standard SI units is crucial. The electric constant \( K \) is used to compute the resultant electric potential due to point charges at a specific location.
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