Point charges of q = -3(nC), located in E = (V/m) uniform electric field are fixed to the two corners of the square with a = 1 (m) edge as in the figure. Find the magnitude of the electric field at point P in (V/m) units. (cos45* = sin45 = √2/2) A) 71√2 B) 26√2 C) B√2 D) 25√2 E) 33√/2 545
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- Two pairs of charges are shown in (Figure 1). Figure AB (b) | II II E F CD I 1 A B C I D ** I E 1 F + I G H I I J I I GHIJ I Part A At which point or points is the electric field zero in (Figure 1)(a)? Enter the letter or letters of the points in alphabetical order without commas. If there are no points where the electric field is zero, enter 0. E,F Submit Previous Answers Request Answer * Incorrect; Try Again; 12 attempts remaining Part B At which point or points is the electric field zero in (Figure 1)(b)? Enter the letter or letters of the points in alphabetical order without commas. If there are no points where the electric field is zero, enter 0. 8.5 Submit Previous Answers Request Answer X Incorrect; Try Again; 14 attempts remaining ReviewThree charges are placed on the ring as shown below. If the charge q is placed symmetrically with respect to other two charges, find the value of the Q. 90° q (a) Q = q (b) 2 = -√2 (c) Q = √√q (d) Q = 2qA test charge of +2µC is placed halfway between a charge of +6µC and another of +4μC separated by distance 2d = 11 cm. +4uC 9₁ = +4 μC The free body diagram of q2 from Part 1 should look like this: +2μC F3-2 d N q2 = +2 μC F1-2 F3→2 > F1→2 +6μС The force on q2 due to q₁ is repulsive and acts to the right. The force on q2 due to q3 is repulsive and acts to the left. (b) Calculate the force on the test charge by the +4μC charge. N (c) Calculate the net force on the test charge by both the charges. X 93 = +6 μC because 93 > 91. (a) Calculate the force on the test charge by the +6μC charge. Hint: The force in the positive x-direction is positive and the negative x direction is negative. N
- At a distance r1 from a point charge, the magnitude of the electric field created by the charge is 392 N/C. At a distance r2 from the charge, the field has a magnitude of 109 N/C. Find the ratio r2/r1.Two point charges are situated in a Cartesian coordinate system as follow: q1=7.0x10^-6 C @ the coordinates (-0.46,0.80)m q2= -3.4x10^-6 C @ the coordinates (0.80,0.36)m What's the direction of the net electric field at the origin (0,0)?What is the electric field at point P due to the two charges shown? +3.1 x 10-6 C -2.2 x 10-6 C (+ + 1.8 m 0.50 m 07.4x104[right] 07.4x10¹ [left] с ● P 2.7x10¹ [right] N с ○2.7x10¹ [left] N
- Three charges are placed on three corners of a square, as shown in the figure. Each side of the square is 24.0 cm. Compute the magnitude and direction of the electric field at the fourth corner. 91 = +4.0 nC 92 = -6.5 nC 93 = -3.5 nCThe figure gives the magnitude of the electric field inside and outside a sphere with a uniformly distributed positive charge. What is the charge (C) on the sphere? Em = 8.00 × 10 N/C, R = 3.00 cm F R 5.60 × 10-7 1.10 × 10-7 6.81 x 10-5 3.56 × 10-7 6.09 × 10-5 O 3.72 x 10-7 2.54 x 10-5 2.12 x 10-5 8.25 x 10-6 4.23 x 10-7Two point charges are situated in a cartesian coordinate system as follow: Q1 = 7.2 x 10^-6 C @ the coordinates (-0.43, 0.62) m Q2 = -4.7 x 10^-6 C @ the coordinates (0.78, 0.43) m What is the direction of the net electric field at the origin (0,0)? Answer this as an angle measured in degrees relative to the +x direction. Let answers in the first 3 quadrants be positive and negative in the 4th quadrant.
- Two point charges of 7.15 x 10^-9 C are situated in a Cartesian coordinate system. One charge is at the origin while the other is at (0.5, 0) m. What is the magnitude of the net electric field at the location (0, 0.75) m?Two point charges are situated in a cartesian coordinate system as follow; 91-9.6 x 10 C @ the coordinates (-0.49, 0.92) m 92= -3.4 x 106 C @ the coordinates (0.74, 0.45) m What is the direction of the net electric field at the origin (0, 0)? Answer this as an angle measured in degrees relative to the +x direction. Let answers in the first 3 quadrants be positive and negative in the 4th quadrant.Question 3. Three charges are at the corners of an equilateral triangle, as shown in Figure 3. Calculate the electric field at a point midway between the two charges on the x-axis. 7.00 με 0.500 m 60.0° 60.0° 2.00 μC -4.00 μC Figure 3: