Point charges of 5.00 µC and–3.00 µC are placed 0.250 m apart. (a) Where can a third charge be placed so that the net force on it is zero? (b) What if both charges are positive?
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A: charge Q1 =5μC and second charge Q2=-3μC disctnace between them L=25m let say thied charge =q now…
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A: The given values are, q1=2.40 pCr1=10 cm=10×10-2 mq2=-4.80 pCr2=20 cm=20×10-2 mr3=10 cm=10×10-2 m
Q: help
A: Approach to solving the question: Coulomb's lawDetailed explanation:
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- Two tiny, spherical water drops, with identical charges of -8.95 × 1016 C, have a center-to-center separation of 1.42 cm. (a) What is the magnitude of the electrostatic force acting between them? (b) How many excess electrons are on each drop, giving it its charge imbalance? (a) Number i Units (b) Number i Unitsa) What is the charge on the other bearing, after separation? b) What was the net charge on both bearings before separation?Two point charges are placed on the x axis. A charge of qA= +4.54 μC is placed at x= 0 and a charge of qB= -2.87 μC is placed at x=d. When a third point charge qC is placed at x= 2.29d, the electric force on the charge at x= 0 doubles in magnitude but maintains its original direction. What is qC?
- Two point charges lie along the y-axis. A charge of q1 = -8 µC is at y = 6.0 m, and a charge of q2 = -6 µC is at y = -4.0 m. Locate the point (other than infinity) at which the total electric field is zero. Need Help? Read ItTwo fixed positively charged balls (q 1 = 1 × 10-ºC; q 2 =?) are separated by a distance d = 0.3 m. If the Coulomb force between the two charges is F = 10-6N, then the charge q2 is equal to: (ke = 9 × 10° N.m²/C²) 10^-9 C 10^-8 C 10^-7 C 10^-2 C 10^-6 CTwo point charges, -25 uC and -75 µC, are held fixed exactly 1.0 m apart. (a) Where should a third charge be placed so that the net force on it is zero? (b) Explain why the magni- tude and sign of the third charge do not affect your answer to part (a).