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Plz solve within 30min I vill give definitely upvote and vill give positive feedback thank you sir( plz solve only part 4 ,5  and 6)

Plz solve within 30min I vill give definitely upvote and vill give positive feedback thank you sir( plz solve only part 4 ,5  and 6)

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Plz solve within 30min I vill give definitely upvote and vill give positive feedback thank you sir( plz solve only part 4 ,5  and 6)

A motion detector measures distance to the nearest object by using a speaker and a microphone. The speaker clicks 30 times a second. The microphone detects the sound bouncing bad from the nearest object in front of it. The computer calculates the time delay between the making of the sound and receiving the echo. It knows the speed of sound (about 343 m/s at room temperature) and from that, it can calculate the distance to the object from the time delay. A. If the nearest object in front of the detector is too far away, the echo will not get back before a second click is emitted. Once that happens, the computer has no way of knowing that the echo isn't an echo from the second click and the detector doesn't give comect results anymore. Once the speaker emits a click, how much time does the echo have to return to the microphone before the next click is emitted? 0.033 VI What's the furthest away the object can be so that the echo returns before the next click is emited? 5.65 m B. The speed of sound changes a little bit with temperature. Let's try to get an idea of how important this is. At room temperature (72F) the speed of sound is about 343 m/s Suppose we are measuring an object that is 3.3 meters away from the detector at 72°F. What is the time delay & that the computer detects before the echo retums? X* Now suppose the object is si 3.3 m from the detector, but the temperature is 62F. What is the speed of sound at this temperature? mis At this speed, what is the time delay & that the computer detects before the echo retums? X. If the computer detects this time delay, but calculates the distance using the speed of sound at 72°F (because it doesn't know the temperature), what is the object's distance that the computer would report? xm
Transcribed Image Text:A motion detector measures distance to the nearest object by using a speaker and a microphone. The speaker clicks 30 times a second. The microphone detects the sound bouncing bad from the nearest object in front of it. The computer calculates the time delay between the making of the sound and receiving the echo. It knows the speed of sound (about 343 m/s at room temperature) and from that, it can calculate the distance to the object from the time delay. A. If the nearest object in front of the detector is too far away, the echo will not get back before a second click is emitted. Once that happens, the computer has no way of knowing that the echo isn't an echo from the second click and the detector doesn't give comect results anymore. Once the speaker emits a click, how much time does the echo have to return to the microphone before the next click is emitted? 0.033 VI What's the furthest away the object can be so that the echo returns before the next click is emited? 5.65 m B. The speed of sound changes a little bit with temperature. Let's try to get an idea of how important this is. At room temperature (72F) the speed of sound is about 343 m/s Suppose we are measuring an object that is 3.3 meters away from the detector at 72°F. What is the time delay & that the computer detects before the echo retums? X* Now suppose the object is si 3.3 m from the detector, but the temperature is 62F. What is the speed of sound at this temperature? mis At this speed, what is the time delay & that the computer detects before the echo retums? X. If the computer detects this time delay, but calculates the distance using the speed of sound at 72°F (because it doesn't know the temperature), what is the object's distance that the computer would report? xm
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