plution of pH 3.88 is prepared by dissolving sufficient ium formate, NaHCOO(s), in 1.50 L of 0.100 M formic acid (HCO ny mol of NaOH(s) must be added to change the pH by 0.40 units ume changes on addition of solids.

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Please give calculation with explanation.
A solution of pH 3.88 is prepared by dissolving sufficient
sodium formate, NaHCOO(s), in 1.50 L of 0.100 M formic acid (HCOOH). How
many mol of NaOH(s) must be added to change the pH by 0.40 units? Assume no
volume changes on addition of solids.
Data: Ka (HCOOH) = 1.8 × 10-4
0.025
0.10
0.070
0.040
Transcribed Image Text:A solution of pH 3.88 is prepared by dissolving sufficient sodium formate, NaHCOO(s), in 1.50 L of 0.100 M formic acid (HCOOH). How many mol of NaOH(s) must be added to change the pH by 0.40 units? Assume no volume changes on addition of solids. Data: Ka (HCOOH) = 1.8 × 10-4 0.025 0.10 0.070 0.040
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