plock of m = 12 kg is placed against the vertical front a cart as shown below. What acceleration must the rt have so that block A does not fall? The coefficient static friction between the block and the are is mg = A ) а. 24.5 m/s2 O b. none of these О с. 36.8 m/s? O d. 6.1 m/s2 D e. 18.4 m/s²

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Q: A body of mass m at rest on the top of a smooth incline slides down. If the height of the incline h…

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Q: Problem: An ice skater moving at 9.0000 m/s coasts to a halt in 95.00 meters on an ice surface. What…

A: Given : vo = 9.0000 m/s v = 0 m/s (because finally skater comes to halt) s = 95.00 m g = 9.807 m/s2…

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A: Force is a vector quantity and their resultant is given by vector addition methods .

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A: Draw the free body diagram. Resolve the forces. ∑Fy:N-mgcosθ=0∑Fx:mgsinθ=maa=gsinθ     (1)

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Q: 6. An 810 kg car accelerates from rest to 27m in a distance of 120 m. What is the magnitude of the…

A: Given : m = 810 kg vo = 0 (because car accelerates from rest) v = 27 m/s s = 120 m

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A: Given- Force (F1) = 11.7 N Acceleration (a) = 10.3 m/s2 θ = 39° Mass of crate (m) = 6.2 Kg

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A: Hi There since the answer for which required is not mention we are providing solution for the first…

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Q: What is the net force from the FBD below? What is the acceleration? M = 10kg.

A: The Second Law of Motion, also known as Newton's Second Law, The net force acting on an object is…

Q: FRICTIONLESS Find the acceleration of m2, in m/s? , if ml = 1.1 kg ,and m2= 80.8 kg M2

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Q: How much force must be applied in order for a 1200 kg car to maintain a velocity of 4 m/s in a…

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Q: 0 = 55.7 deg ß = 53.8 deg Mass of the traffic light = 109 kg Find the tension T2 T1 T2 T3 60

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Q: D

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Q: A 90 kg Panda is sliding down a bamboo at a constant speed of 2.4 m/s. The friction on the Panda is…

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Q: An object of mass 5kg is sliding with a constant velocity of 10m/s on a frcitionless horizontal…

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Q: A trucks brakes fail while driving down a hill at a speed of 92 km/hr at the emergency ramp shown.…

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Q: 8. Hector drives a pickup truck horizontally at 15 m/s. He is transporting a crate of delicate lead…

A: thank you

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Q: H.W: Two blocks connected by a cord passing over a small frictionless pulley rest on frictionless…

A: According to Newton's second law Net force =mass×acceleration FBD of the block and the system:

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Q: PROBLEM 5.21 25. Determine the magnitude of W in Figure below so that the 200-lb body will have an…

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A: Given that, Force F = 20 N Mass M = 5.0 kg Angle = 30o

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Q: 2. A block is given an initial velocity of vị up a frictionless incline of angle 0. How far up the…

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Q: A 16kg crate resting on a horizontal surface is pushed as shown. If the coefficient of static…

A: Given: mass of crate m = 16 kgcoefficient of static friction μ = 0.19

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Q: In the figure shown, mi= 15 kg. the coefficient of kinetic friction between mi and the surface is…

A: SOlution: Given that m1 = 15 kg friction coef = 0.2 inclination angle = 30 degree

Q: The figure shows a 7.0 kg block slides down on an inclined rough plane at constant acceleration of…

A: Mass, m= 7.0 kg Acceleration, a = 2.0 m/s^2 Angle of inclination, = 30 degrees Taking g= 9.8 m/s^2

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Newton's Second Law

Newton’s laws of motion describe the relationship between the motion of an object and forces acting on it. Newton’s law of motion has two types as follows: