plem 1220: A weight of 96.6 lb is fastened to a cord nich is wrapped around a solid cylinder of 3 ft. dius weighing 322 Ib. The cylinder rotates about its prizontal controidal axis. Compute the angular cceleration and the tension in the cord; also the otal bearing reaction. W = 322 lb ( 322)

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Chapter1: Units, Trigonometry. And Vectors
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What torque applied to the cylinder of prob 1220 will raise the weight with an acceleration of 13 ft/sec? What will be the total bearing reaction?
Cont:
96.6-T 9a – Eq.2
%3D
Multiply Eq.2 by 3:
289.8-37T = 27a
%3D
3T = 45a
Adding the two equation:
289.8
72a
%3D
a = 4.03 rad/sec
Subst. a from (1)
3T = 45a
T= 60.5 lb
EF = 0
R= 322 +60.5
%3D
%3D
R
382.5 lb
Transcribed Image Text:Cont: 96.6-T 9a – Eq.2 %3D Multiply Eq.2 by 3: 289.8-37T = 27a %3D 3T = 45a Adding the two equation: 289.8 72a %3D a = 4.03 rad/sec Subst. a from (1) 3T = 45a T= 60.5 lb EF = 0 R= 322 +60.5 %3D %3D R 382.5 lb
Problem 1220: A weight of 96.6 Ib is fastened to a cord
which is wrapped around a solid cylinder of 3 ft.
radius weighing 322 Ib. The cylinder rotates about its
horizontal controidal axis. Compute the angular
acceleration and the tension in the cord; also the
total bearing reaction.
W = 322 Ib
322
Ī= ½Mr² = ½
(3)²
32.2,
%3D
3'
I = 45lb – ft. sec?
%3D
ΣΜ-Ια
3T = 45a – Eq. 1
%3D
ΣΧ
a
-
g
96. 6
96.6 - Т -
(За)
32.2
a = a
96 6-T= 3(3a)
%3D
Transcribed Image Text:Problem 1220: A weight of 96.6 Ib is fastened to a cord which is wrapped around a solid cylinder of 3 ft. radius weighing 322 Ib. The cylinder rotates about its horizontal controidal axis. Compute the angular acceleration and the tension in the cord; also the total bearing reaction. W = 322 Ib 322 Ī= ½Mr² = ½ (3)² 32.2, %3D 3' I = 45lb – ft. sec? %3D ΣΜ-Ια 3T = 45a – Eq. 1 %3D ΣΧ a - g 96. 6 96.6 - Т - (За) 32.2 a = a 96 6-T= 3(3a) %3D
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