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MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A company surveyed 2500 men where 1300 of the men identified themselves as the primary grocery shopper in their household. a) Estimate the percentage of all males who identify themselves as the primary grocery shopper. Use a 98% confidence interval. Check the conditions first. b) A grocery store owner believed that only 42% of men are the primary grocery shopper for their family, and targets his advertising accordingly. He wishes to conduct a hypothesis test to see if the fraction is in fact higher than 42%. What does your confidence interval indicate? Explain. c) What is the level of significance of this test? Explain. a) Check the conditions for constructing a confidence interval. Select all necessary conditions that have thecanciato aualongtion below. Question Viewer YA. 10% Condition: This condition is satisfied because 2500 men are less than 10% of the population of men. O B. Nearly Normal Condition: This condition is satisfied because there is nothing to indicate that the underlying population is not Normal. O C. Nearly Normal Condition: This condition is not satisfied because it is highly unlikely that the population of men is Normal. D. Success/Failure, Condition: This condition is not satisfied because there were fewer than either 10 successes or failures. Randomization Condition: This condition is satisfied because there is nothing to indicate that the samples were not drawn randomly. This Randomization Condition: This .condition is not satisfied because the samples were drawn from a convenience sample. Ten YG. Success/Failure Condition: This condition is satisfied because there were more than 10 successes and failures. O H. 10% Condition: This condition is not satisfied because 2500 men are more than 10% of the population of men. Construct a 98% confidence interval for the sample proportion. The 98% confidence interval is (0.457 0.503). (Round to three decimal places as needed.)
Transcribed Image Text:A company surveyed 2500 men where 1300 of the men identified themselves as the primary grocery shopper in their household. a) Estimate the percentage of all males who identify themselves as the primary grocery shopper. Use a 98% confidence interval. Check the conditions first. b) A grocery store owner believed that only 42% of men are the primary grocery shopper for their family, and targets his advertising accordingly. He wishes to conduct a hypothesis test to see if the fraction is in fact higher than 42%. What does your confidence interval indicate? Explain. c) What is the level of significance of this test? Explain. a) Check the conditions for constructing a confidence interval. Select all necessary conditions that have thecanciato aualongtion below. Question Viewer YA. 10% Condition: This condition is satisfied because 2500 men are less than 10% of the population of men. O B. Nearly Normal Condition: This condition is satisfied because there is nothing to indicate that the underlying population is not Normal. O C. Nearly Normal Condition: This condition is not satisfied because it is highly unlikely that the population of men is Normal. D. Success/Failure, Condition: This condition is not satisfied because there were fewer than either 10 successes or failures. Randomization Condition: This condition is satisfied because there is nothing to indicate that the samples were not drawn randomly. This Randomization Condition: This .condition is not satisfied because the samples were drawn from a convenience sample. Ten YG. Success/Failure Condition: This condition is satisfied because there were more than 10 successes and failures. O H. 10% Condition: This condition is not satisfied because 2500 men are more than 10% of the population of men. Construct a 98% confidence interval for the sample proportion. The 98% confidence interval is (0.457 0.503). (Round to three decimal places as needed.)
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