Please use Matlab to solve the question. Develop an algorithm to transform a number to binary floating point form for both single and double precision. Write a user-defined MatLab function that has as input arguments the number y and the precision p (1 single precision, 2 double precision). If the input is one argument, the program automatically should select single precision. The function should evaluate only numbers with absolute values between 2-100 and 2100 and should show an error for numbers outside of this range. The output arguments should be three numbers in binary form: the sign, the exponent+bias and the mantissa.The algorithm should be explained with steps (1, 2, 3...). The only built-in functions of MatLab you are allowed to use are the following: fprintf, rem, mod, input, nargin, abs, sign, error, zeros, clearvars, close, clc
Please use Matlab to solve the question. Develop an algorithm to transform a number to binary floating point form for both single and double precision. Write a user-defined MatLab function that has as input arguments the number y and the precision p (1 single precision, 2 double precision). If the input is one argument, the program automatically should select single precision. The function should evaluate only numbers with absolute values between 2-100 and 2100 and should show an error for numbers outside of this range. The output arguments should be three numbers in binary form: the sign, the exponent+bias and the mantissa.The algorithm should be explained with steps (1, 2, 3...). The only built-in functions of MatLab you are allowed to use are the following: fprintf, rem, mod, input, nargin, abs, sign, error, zeros, clearvars, close, clc
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Can you use Matlab
Thanks
![Please use Matlab to solve the question.Develop an algorithm to transform a number to binary floating point form for
both single and double precision. Write a user-defined MatLab function that has as input arguments the number y and
the precision p (1 single precision, 2 double precision). If the input is one argument, the program automatically should
select single precision. The function should evaluate only numbers with absolute values between 2-100 and 2100 and
should show an error for numbers outside of this range. The output arguments should be three numbers in binary form:
the sign, the exponent+bias and the mantissa.The algorithm should be explained with steps (1, 2, 3...). The only built-in
functions of MatLab you are allowed to use are the following: fprintf, rem, mod, input, nargin, abs, sign, error, zeros,
clearvars, close, clc](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7f1f56f6-a769-4b12-a499-cf1e3f7149ba%2F998b0750-ff4e-48ee-b610-6b0672fa347a%2Fsr38hu_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Please use Matlab to solve the question.Develop an algorithm to transform a number to binary floating point form for
both single and double precision. Write a user-defined MatLab function that has as input arguments the number y and
the precision p (1 single precision, 2 double precision). If the input is one argument, the program automatically should
select single precision. The function should evaluate only numbers with absolute values between 2-100 and 2100 and
should show an error for numbers outside of this range. The output arguments should be three numbers in binary form:
the sign, the exponent+bias and the mantissa.The algorithm should be explained with steps (1, 2, 3...). The only built-in
functions of MatLab you are allowed to use are the following: fprintf, rem, mod, input, nargin, abs, sign, error, zeros,
clearvars, close, clc
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Hello,it s incorrect
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Insufficient number of input parameters.
Error untitled2 (line 9)
if abs(y) < 2^-100 || abs(y) > 2^100
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