please solve using CONJUGATE BEAM METHOD O Pab 2l -b)PL3EIPL?Og =2EIPLPL?16EIPx2(3L² – 4x*) 0 sxs48EI48EI6E 3L – x)Ph(L -9/3LEIPhx(L -x - b)OSxsaPx2GLEI-(21 - a)Pab6L EIE (3a - x) 0SxsaB6EIPa?dn =AE (3L - a)Og =-PaPb (L.at xVPah6EI2EI(21 -b)6LEIPa?(3x- a) a SXSL6EIPh(31-46) if a >bSaerT48EISwl(L'- 21.x +x')Smar384EI- - AEI24EI-(6L – 4Lx+x²)OB =6EI24EISEI2L Ela - 21)² + 2a(a - 21.)x + Lx daer (S2 - 121b+ 84y241. EI(SL - 121b + 8A)384EI(a - 2L)WoOSxsa241. EIif a zbME(6a - 4ax+x) 0sxs a24EIWoa24ET AL - a) Og =-(-L+x)(a - 4Lx + 2x)SanterKET (3L - 2a) if asb 34LET (21. -a")(31 - 2a) if a sb24L. EI6EI24L. EI96EIWpa"24E (4x - a)asxsLda 0.006 522"El360EI(7L* – 102x² + 3x*)at x- 0.51931360LEISio "LSar-0.006 510EI45 EIwoLA120L ET (10L' – 10L²X+5Lx² – x³) | ôp =24EI30EIat xAMax(L-x)6LEIE19 vaMol9/3EI6EIMoLMox?SanerMoLOg =EI16EI3EIMo2EI2EI

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Answered: please solve using CONJUGATE BEAM…

Engineering

Civil Engineering

please solve using CONJUGATE BEAM METHOD

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Matrix Algebra for Structural analysis

Structural analysis is a process in which the effects of different loads and internal forces, acting on structures and their elements are determined. This method of analysis is effective in detecting the failure loads of the structural elements and the design can be altered before commencing the construction process, which ensures proper strength and safety of the structures.

Question

please solve using CONJUGATE BEAM METHOD

O Pab 2l -b)
PL
3EI
PL?
Og =
2EI
PL
PL?
16EI
Px2
(3L² – 4x*) 0 sxs
48EI
48EI
6E 3L – x)
Ph(L -
9/3LEI
Phx
(L -x - b)
OSxsa
Px2
GLEI
-(21 - a)
Pab
6L EI
E (3a - x) 0Sxsa
B
6EI
Pa?
dn =AE (3L - a)
Og =-
Pa
Pb (L.
at xV
Pah
6EI
2EI
(21 -b)
6LEI
Pa?
(3x- a) a SXSL
6EI
Ph
(31-46) if a >b
SaerT
48EI
Swl
(L'- 21.x +x')
Smar
384EI
- - AEI
24EI
-(6L – 4Lx+x²)
OB =
6EI
24EI
SEI
2L Ela - 21)² + 2a(a - 21.)x + Lx daer (S2 - 121b+ 84y
241. EI
(SL - 121b + 8A)
384EI
(a - 2L)
Wo
OSxsa
241. EI
if a zb
ME(6a - 4ax+x) 0sxs a
24EI
Woa
24ET AL - a) Og =-
(-L+x)(a - 4Lx + 2x)
Santer
KET (3L - 2a) if asb 34LET (21. -a")
(31 - 2a) if a sb
24L. EI
6EI
24L. EI
96EI
Wpa"
24E (4x - a)
asxsL
da 0.006 522
"
El
360EI
(7L* – 102x² + 3x*)
at x- 0.51931
360LEI
Sio "L
Sar-0.006 510
EI
45 EI
woL
A
120L ET (10L' – 10L²X+5Lx² – x³) | ôp =
24EI
30EI
at xA
Max
(L-x)
6LEI
E19 va
Mol
9/3EI
6EI
MoL
Mox?
Saner
MoL
Og =
EI
16EI
3EI
Mo
2EI
2EI

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