Please solve the problem number one using figure 2.1 EXERCISES1. Which of the strings 0001, 01101, 00001101 are accepted by the dfa inFigure 2.1? the initial vertex, while those labeled with qf E F are the final vertices.It is a trivial matter to convert from the (Q, Σ, 6, qo, F) definition of a dfato its transition graph representation and vice versa.EXAMPLE 2.1The graph in Figure 2.1 represents the dfawhere & is given by0M = ({90, 91, 92}, {0, 1}, 8, 90, {91}),90This dfa accepts the string 01. Starting in state go, the symbol 0 is readfirst. Looking at the edges of the graph, we see that the automatonremains in state 90. Next, the 1 is read and the automaton goes intostate 91. We are now at the end of the string and, at the same time,in a final state 9₁. Therefore, the string 01 is accepted. The dfa doesnot accept the string 00, since after reading two consecutive O's, it willbe in state go. By similar reasoning, we see that the automaton willaccept the strings 101, 0111, and 11001, but not 100 or 1100.FIGURE 2.18 (90,0) = 90,8 (91,0) = 90,8 (92,0) = 92,018 (90, 1) = 91,8 (91,1) = 92,8 (92, 1) = 91.911192

Answered: Please solve the problem number one…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Please solve the problem number one using figure 2.1

EXERCISES
1. Which of the strings 0001, 01101, 00001101 are accepted by the dfa in
Figure 2.1?

the initial vertex, while those labeled with qf E F are the final vertices.
It is a trivial matter to convert from the (Q, Σ, 6, qo, F) definition of a dfa
to its transition graph representation and vice versa.
EXAMPLE 2.1
The graph in Figure 2.1 represents the dfa
where & is given by
0
M = ({90, 91, 92}, {0, 1}, 8, 90, {91}),
90
This dfa accepts the string 01. Starting in state go, the symbol 0 is read
first. Looking at the edges of the graph, we see that the automaton
remains in state 90. Next, the 1 is read and the automaton goes into
state 91. We are now at the end of the string and, at the same time,
in a final state 9₁. Therefore, the string 01 is accepted. The dfa does
not accept the string 00, since after reading two consecutive O's, it will
be in state go. By similar reasoning, we see that the automaton will
accept the strings 101, 0111, and 11001, but not 100 or 1100.
FIGURE 2.1
8 (90,0) = 90,
8 (91,0) = 90,
8 (92,0) = 92,
0
1
8 (90, 1) = 91,
8 (91,1) = 92,
8 (92, 1) = 91.
91
1
1
92

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Step 1

Introduction

DFA:

The deterministic finite automata (DFA) is just a mathematical concept used to identify trends in a stream of input characters. It has a start state, a set of accepted states, a transition mechanism, a collection of states, a collection of input symbols, and a set of states. The DFA receives an input symbol at each step and changes states in accordance with the transition function. The input is accepted if the end phase is an accepting state; else, it is rejected. DFAs are often employed in natural language processing, pattern recognition, and compiler design.

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Strings accepted by DFA.

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