Please show your manual solutions on how to get the 0.648 value. The circle green in the figure.   Notes : I need manual solutions how get 0.648   Civil engineering- steel design

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Please show your manual solutions on how to get the 0.648 value. The circle green in the figure.

 

Notes : I need manual solutions how get 0.648

 

Civil engineering- steel design

 

 

Question
Determine the nominal tensile strength based on the effective area (A₂) (see below).
2 L5x3x4 LLBB
(two angles, long legs
back-to-back)
A242 steel
5"
о о
<3" →
7/8-in.-diameter bolts
Transcribed Image Text:Question Determine the nominal tensile strength based on the effective area (A₂) (see below). 2 L5x3x4 LLBB (two angles, long legs back-to-back) A242 steel 5" о о <3" → 7/8-in.-diameter bolts
5"
As
O
=
3"
◄ ►
Step 2
The Gross area of the given section is
3. 88 in².
21.5x3x1/4LLBB
The formula to calculate the net area of the section
is given by,
An = Ag - Σtdh
. (1)
Here, Ag is the gross area, An is the net area, and t
is the thickness of the plate, dh is the diameter of
the hole.
Substitute all the values in equation (1).
An=3. 88 (4×) (²} + })
= 2.88 in²
The formula to calculate the reduction factor is
given by,
X
U = 1
ī
Here, U is the reduction factor, x is the distance
from the centroid of the connected area to the
plane of connection, and I is the length of the
connection.
Substitute all the values in equation (2).
U=1 _ 0.648
-
3
Transcribed Image Text:5" As O = 3" ◄ ► Step 2 The Gross area of the given section is 3. 88 in². 21.5x3x1/4LLBB The formula to calculate the net area of the section is given by, An = Ag - Σtdh . (1) Here, Ag is the gross area, An is the net area, and t is the thickness of the plate, dh is the diameter of the hole. Substitute all the values in equation (1). An=3. 88 (4×) (²} + }) = 2.88 in² The formula to calculate the reduction factor is given by, X U = 1 ī Here, U is the reduction factor, x is the distance from the centroid of the connected area to the plane of connection, and I is the length of the connection. Substitute all the values in equation (2). U=1 _ 0.648 - 3
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