Please show all steps to reach answers provided. Final Test review 6. A simply supported beam carries two point-loads as shown below. If the maximum allowable shear stress is 40.0 MPa, and the maximum bending stress allowed is 100 MPa: Draw the deflected shape, SFD, and BMD ii. Locate the centroid above the base and the moment of inertia (I) of the cross-section What is the highest value of P allowed? 200 5.0 15.0 2.00 m 230 2.00 m 15.0 8.00 m 6.0번 150 Note: Self-weight may be ignored CROSS - SECTION Answers: Note: Student should draw the SFD, BMD and Deflected shape. Use the coordinates given below to check answers. SFD: (0.00m, P kN): (2.00m, P kN): (6.00m, -P kN), (8.00m, -P kN) BMD: (0.00m, 0.00 kNm): (2.00m, 2P kNm): (6.00m, 2P kNm), (8.00m, 0.00 kNm) Deflected shape: smile throughout! (i) = 157 mm from base; I, = 85.6 x 10° mm (ii) At N.A., Q = 397.6 x 10' mm. Using fy = VQ/(It) where fy = 40.0 N/mm, t = 6.00 mm Ix = 85.6 x 10° mm“ and V = P yields P = 51.7 kN Using fu = ("/1ly where fs = 100 N/mm, y = 157 mm, I, = 85.6 x 10° mm and M = 2P yields P = 27.2 kN. The Point load allowable is the less of the two values computed above. Therefore P = 27.2 kN
Please show all steps to reach answers provided. Final Test review 6. A simply supported beam carries two point-loads as shown below. If the maximum allowable shear stress is 40.0 MPa, and the maximum bending stress allowed is 100 MPa: Draw the deflected shape, SFD, and BMD ii. Locate the centroid above the base and the moment of inertia (I) of the cross-section What is the highest value of P allowed? 200 5.0 15.0 2.00 m 230 2.00 m 15.0 8.00 m 6.0번 150 Note: Self-weight may be ignored CROSS - SECTION Answers: Note: Student should draw the SFD, BMD and Deflected shape. Use the coordinates given below to check answers. SFD: (0.00m, P kN): (2.00m, P kN): (6.00m, -P kN), (8.00m, -P kN) BMD: (0.00m, 0.00 kNm): (2.00m, 2P kNm): (6.00m, 2P kNm), (8.00m, 0.00 kNm) Deflected shape: smile throughout! (i) = 157 mm from base; I, = 85.6 x 10° mm (ii) At N.A., Q = 397.6 x 10' mm. Using fy = VQ/(It) where fy = 40.0 N/mm, t = 6.00 mm Ix = 85.6 x 10° mm“ and V = P yields P = 51.7 kN Using fu = ("/1ly where fs = 100 N/mm, y = 157 mm, I, = 85.6 x 10° mm and M = 2P yields P = 27.2 kN. The Point load allowable is the less of the two values computed above. Therefore P = 27.2 kN
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Please show all steps to reach answers
provided.
Final Test review
6. A simply supported beam carries two point-loads as shown below. If the
maximum allowable shear stress is 40.0 MPa, and the maximum bending stress
allowed is 100 MPa:
Draw the deflected shape, SFD, and BMD
Locate the centroid above the base and the moment of inertia (Ix) of the
cross-section
What is the highest value of P allowed?
200
P
15.0
15.0
230
2.00 m
2.00 m
15.0
8.00 m
6.0d
150
Note: Self-weight may be ignored
CROSS - SECTION
Answers:
Note: Student should draw the SFD, BMD and Deflected shape. Use the coordinates given below to check answers.
SFD: (0.00m, P kN): (2.00m, P kN): (6.00m, -P kN), (8.00m, -P kN)
BMD: (0.00m, 0.00 kNm): (2.00m, 2P kNm); (6.00m, 2P kNm), (8.00m, 0.00 kNm)
Deflected shape: smile throughout!
(i)
= 157 mm from base; I, = 85.6 x 10° mm
(ii)
Using fy = VQ/(It) where f, = 40.0 N/mm, t = 6.00 mm Ix = 85.6 x 10° mm“ and V = P
yields P = 51.7 kN
At N.A., Q = 397.6 x 10° mm.
Using fs = ("/1ly where fs = 100 N/mm, y = 157 mm, Ix = 85.6 x 10° mm“ and M = 2P
yields P = 27.2 kN.
The Point load allowable is the less of the two values computed above. Therefore P = 27.2
KN
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