Determine the equivalent impedance across 'a' and 'b'. j120 5.2 W 4.2 j9n be ww 4.0 j130 j112 j20Ω 8.2. MM ΖΩ j8n
Determine the equivalent impedance across 'a' and 'b'. j120 5.2 W 4.2 j9n be ww 4.0 j130 j112 j20Ω 8.2. MM ΖΩ j8n
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
Basic Electrical Engineering (UPVOTE WILL BE GIVEN. PLEASE WRITE THE COMPLETE SOLUTIONS LEGIBLY. NO LONG EXPLANATION NEEDED. ANSWER IN 4 DECIMAL PLACES. BOX THE FINAL ANSWERS.
![Determine the equivalent impedance across 'a' and 'b'.
j12Ω 5Ω
(00)
Μ
4Ω
j9n
2
ww
4Ω
j13Ω
j112
@j20Ω
8Ω.
WM
ΖΩ
j8Ω](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F02f250f6-982c-4851-a985-0bfcf3502c0e%2F3a389513-a500-4939-8a5f-89295517c5c6%2Fkz9mg4p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Determine the equivalent impedance across 'a' and 'b'.
j12Ω 5Ω
(00)
Μ
4Ω
j9n
2
ww
4Ω
j13Ω
j112
@j20Ω
8Ω.
WM
ΖΩ
j8Ω
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Follow-up Questions
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Follow-up Question
Please resolve the problem above. The same givens/values above but follow the way of solving in the attached photo.
![1. Determine the equivalent impedance across 'a' and 'b'.
home m
M
1.22
j6Ω
M
2.522
j12
j10Ω 4Ω
W
W
jon
j152
3.2
Ans:
Zab
Zab = 17.4966/74.44°
: 4.6932 + j16.8554 Ω
5.2
j7
b
Gotham
(+)+(5)
4+jlo
2+
vize 3.5
ed
ut
Aller
зјол
Zeb
1541
Zcd
5
ja
Zbo
LUM
a
bilo
45
زودتر
Zabe
Zb
Zeg
Z
= imaginary
па
Zeg
2
j 12 & 3 jq
py d
Zd
Zbd=
=35.8799/82.2727
с
bzc
Zeq Zad
Zeg = 6,3238+113.4691
cd=
Zc Zbt Zc Zdt Z bZd
Zb
zb
2db = (1+; 4) + (216 + 2)²
Zcd= 8.6+j27.8=29 07972/100912
Zab
Zob
Zeg
Zcd= 8.6+j27.8=29.0998/12:001/72 db = ²c2b + 2c 2d + 2b zd
Zcb = -1 +j46 = 46.0109 291.2454.52
|Zab=4.6932 +j16.8555 Zod=48243 +j35.5541
Zab=17.4967 274.44075
Zd
Zc Zb+ ZcZd + Zb Zd
Zc
لموان
دل
-Tak
A=Zc=2 tj 12
B=Zd=3+;9
c=²6=j15
R
-|F
+](https://content.bartleby.com/qna-images/question/02f250f6-982c-4851-a985-0bfcf3502c0e/075d97c1-6363-476a-bc7a-e6e87a309d46/s6yt8sv_thumbnail.jpeg)
Transcribed Image Text:1. Determine the equivalent impedance across 'a' and 'b'.
home m
M
1.22
j6Ω
M
2.522
j12
j10Ω 4Ω
W
W
jon
j152
3.2
Ans:
Zab
Zab = 17.4966/74.44°
: 4.6932 + j16.8554 Ω
5.2
j7
b
Gotham
(+)+(5)
4+jlo
2+
vize 3.5
ed
ut
Aller
зјол
Zeb
1541
Zcd
5
ja
Zbo
LUM
a
bilo
45
زودتر
Zabe
Zb
Zeg
Z
= imaginary
па
Zeg
2
j 12 & 3 jq
py d
Zd
Zbd=
=35.8799/82.2727
с
bzc
Zeq Zad
Zeg = 6,3238+113.4691
cd=
Zc Zbt Zc Zdt Z bZd
Zb
zb
2db = (1+; 4) + (216 + 2)²
Zcd= 8.6+j27.8=29 07972/100912
Zab
Zob
Zeg
Zcd= 8.6+j27.8=29.0998/12:001/72 db = ²c2b + 2c 2d + 2b zd
Zcb = -1 +j46 = 46.0109 291.2454.52
|Zab=4.6932 +j16.8555 Zod=48243 +j35.5541
Zab=17.4967 274.44075
Zd
Zc Zb+ ZcZd + Zb Zd
Zc
لموان
دل
-Tak
A=Zc=2 tj 12
B=Zd=3+;9
c=²6=j15
R
-|F
+
Solution
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