Please refer to Figure 3, which shows the pattern of interference fringes for light of wavelength 574 nm passing through two narrow slits, projected onto a screen a distance of 1.90 m away. The distance on the screen between the centers of two adjacent bright fringes is 0.77 cm. What is the distance
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A: YOUNG'S DOUBLE SLIT
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- The two most prominent wavelengths in the light emitted by a hydrogen discharge lamp are 656 nm (red) and 486 nm (blue). Light from a hydrogen lamp illuminates a diffraction grating with 460 lines/mm , and the light is observed on a screen 1.5 m behind the grating. What is the distance between the first-order red and blue fringes? Express your answer to two significant figures and include the appropriate units.The spacing between two slits is 5.90×10^-3 m in a Young's double slit experiment. The distance from the slits to the screen is 1.00 m, and the distance from the central bright maximum to the third maxima is 2.50x10^-4 m. Determine the wavelength of the incident light used in the experiment. Include a labelled diagram.Calculate the width the interference fringe in the middle of the screen between two slits given the wavelength of the incident light is 444 nm and the distance between the slits is 0.013 mm. Take the distance between the slits and the screed D=1 m. Provide your answer in millimetres (mm).
- State the conditions necessary for interference to take place. In a Young's 2-slit experiment, the separation of the interference bands ?w is given by the equation: ?=??/? where ? is the wavelength of the light, ? is the distance from the double slit to the screen and ? is the distance between the slits. Given that ?=5 m, ?=0.25 cm and ? 618 nm, calculate the fringe width ?. Give your answer in millimetres.In an interference experiment using a monochromatic source emitting light of wavelength 1, the fringes are produced by two long, narrow slits separated by a distance d. The fringes are formed on a screen which is situated at a distance D >> d.Write down an expression for the fringe width w. Please use "*" for products (e.g. B*A), "/" for ratios (e.g. B/A) and the usual "+" and "-" signs as appropriate. Use "lambda" (without the quotes) for 1 in the equation box. For example, use d*lambda for d2. Please use the "Display response" button to check you entered the answer you expect. w=air 1. n = 1 [a] The figure shows a soap film of thickness dį in air. Light impinges on the film with an angle of incidence 01 and is reflected and refracted at the interfaces. Rays 1 and 2 represents reflected light, while rays 3 and 4 represent light that has been transmitted into the glass. soap \[c] n, = 1.33 |d [b] air n= 1 3 4 The bracketed letters (a], [b], and [c] indicate reflections at the air-soap, and soap-air interfaces. For which of these reflections does a phase change of n occur? Check all that apply. [a] [b] O (c)
- The figure shows a double slit located a distance x = 3.15 m from a screen, with the distance from the center of the screen to a bright fringe given by y. When the distance d between the slits is large compared to the wavelength λ, there will be numerous such bright fringes. Calculate the distance between adjacent fringes, in centimeters, for 640-nm light falling on double slits separated by 0.0785 mm. You may assume that θ is small.please helpLight with a single wavelength of 1 = 461 nm goes through two narrow slits. The light strikes a screen which is a distance L = 2.77 m away. The resulting light intensity pattern is shown below. Each slit has a width of "a", and the separation of the slits is "d". a L a. The interference pattern has its 4-th dark spot (destructive interference) at a distance of y4 = 3.59 mm from the central bright spot. What is the separation "d" between the two slits? Convert your answer to millimeters. (Be careful. The first dark spot is m = 0!) mm b. What is the angle, 0, to this 4-th dark spot of the interference pattern? degrees c. If the 4-th dark spot of the interference pattern is at the same location of the first dark spot of the diffraction pattern, what is the width of each slit "a"? Convert your answer to millimeters. mm be
- Calculate the width the interference fringe in the middle of the screen between two slits given the wavelength of the incident light is 565 nm and the distance between the slits is 0.011 mm. Take the distance between the slits and the screed D=1 m. Provide your answer in millimetres (mm).Green light has a wavelength of approximately 510 nm. When green light is diffracted through a single slit with a width of 30 mm, the observed separation of the first dark fringe and the central maximum is 3.6 cm. Determine the distance between the slit and the screen for this observation to have been madeIn a Young's double slit experiment the wavelength of light is ?λ, separation between the slits is ?a and the distance to the screen is ?D. Give an expression for the interference fringe width ?w on screen if ?≫?D≫a. For Greek letters such as ?λ use the text equivalent - e.g. "lambda" (without the quotes, e.f. for ??Dλ use D*lambda).