Please refer to Figure 2. A light beam shines through air and then strikes a mirror, making an angle theta = 54.6 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h 1.30 cm, located a distance y = 40.3 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of x? 23.0 cm 69.0 cm 34.5 cm 57.5 cm 0 Mirror Glass (n=1.5) Air (n=1)

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Please refer to Figure 2. A light beam shines through air and then strikes a mirror, making an angle theta
= 54.6 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of
thickness h = 1.30 cm, located a distance y = 40.3 cm from the mirror, and then exits the glass pane at the
bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of x? 23.0 cm
69.0 cm 34.5 cm 57.5 cm
Ꮎ
Mirror
3
Glass (n=1.5)
X
Air (n=1)
Transcribed Image Text:Please refer to Figure 2. A light beam shines through air and then strikes a mirror, making an angle theta = 54.6 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h = 1.30 cm, located a distance y = 40.3 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of x? 23.0 cm 69.0 cm 34.5 cm 57.5 cm Ꮎ Mirror 3 Glass (n=1.5) X Air (n=1)
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