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Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter2: Equations And Inequalities

Section2.1: Equations

Problem 54E

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Please note that I have question about an answer posted to one of my questions. Specifically, please explain how the value of .79389 is derived. Also, what is the value of the greek letter? Thank you.

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Given that the mean is 9 and variance is 13.5, find the probability that a light bulb will last between 6 and 12 months INCLUSIVE.

b.
(6-9)х - теаn 12-9
V13.5 Jvar(x) V13.5
P(6< X < 12) = P
= P(-0.82< z< 0.81)
= 9 (0.82)–9(-0.82)
= 9 (0.82)–1+9(0.82)
= 9 (0.82)×2-1
= 2* 0.79389 -1
= 0.58778

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