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Please, I want the same solution, but with a clear line Please help me

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please, I want the same solution, but with a clear line Please help me
Homework: A 1.2gm sample of a mixture of (Na₂CO3 + NaHCO3) is dissolved and titrated with 0.5N HCI. With phenolphthalein, the endpoint is at 15ml while after further addition of methyl orange a second endpoint is at 22ml. Calculate the percentage composition of the mixture. phenolphthaleen gives colour with only Na₂CO3. на Nancoz на , на соз methyl orange. No. of milli equivalents of Na₂ coz = No. of milli equivalents of HC 0.5N HC x15ml = 7.5 milliequivalents -3 :: 7.5 milli equivalents of Na₂CO3 = 7.5×10²³ equivalents . Максоз phenolphthalein mass of Na₂a = No. of equivalents x equivalent mass 7.5×10²³ x 106 (Here change -3 is Na₂ Co₂ to Nancos) 0.795g Naço3 out of 1.2g mixture, 0.7959 Na₂603 "% of Nazcoz = 0.795 ²x100= 66.25% Nazcoz 1.2 1. оз мансоз = 100-66-25= 33-75%, мансоз
Transcribed Image Text:Homework: A 1.2gm sample of a mixture of (Na₂CO3 + NaHCO3) is dissolved and titrated with 0.5N HCI. With phenolphthalein, the endpoint is at 15ml while after further addition of methyl orange a second endpoint is at 22ml. Calculate the percentage composition of the mixture. phenolphthaleen gives colour with only Na₂CO3. на Nancoz на , на соз methyl orange. No. of milli equivalents of Na₂ coz = No. of milli equivalents of HC 0.5N HC x15ml = 7.5 milliequivalents -3 :: 7.5 milli equivalents of Na₂CO3 = 7.5×10²³ equivalents . Максоз phenolphthalein mass of Na₂a = No. of equivalents x equivalent mass 7.5×10²³ x 106 (Here change -3 is Na₂ Co₂ to Nancos) 0.795g Naço3 out of 1.2g mixture, 0.7959 Na₂603 "% of Nazcoz = 0.795 ²x100= 66.25% Nazcoz 1.2 1. оз мансоз = 100-66-25= 33-75%, мансоз
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