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please help with the following! A compound with the formula C6H10 reacts with one equivalent of Br2 in CC14. When that same C6H10 compound was treated with a hot, basic solution of KMnO4, followed by acidic workup, a product was formed whose IR spectrum included a sharp intense peak near 1700 cm-1 and a broad medium absorption from 2500 to 3300 cm-1. The 1H and 13C NMR spectra are shown. Draw the structure of C6H10 and relate your structure to the observed IR and NMR spectra 14 13 12 11 10 6 9 8 Chemical shift (ppm) 4 3 ₂ 1 0 250 The signal at 39 ppm is due to the NMR solvent, not the compound of interest. 200 150 100 Chemical shift (ppm) 50 0

please help with the following! A compound with the formula C6H10 reacts with one equivalent of Br2 in CC14. When that same C6H10 compound was treated with a hot, basic solution of KMnO4, followed by acidic workup, a product was formed whose IR spectrum included a sharp intense peak near 1700 cm-1 and a broad medium absorption from 2500 to 3300 cm-1. The 1H and 13C NMR spectra are shown. Draw the structure of C6H10 and relate your structure to the observed IR and NMR spectra 14 13 12 11 10 6 9 8 Chemical shift (ppm) 4 3 ₂ 1 0 250 The signal at 39 ppm is due to the NMR solvent, not the compound of interest. 200 150 100 Chemical shift (ppm) 50 0

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question: please help with the following! A compound with the formula C6H10 reacts with one equivalent of Br2 in CCI4. When that same C6H10 compound was treated with a hot, basic solution of KMnO4, followed by acidic workup, a product was formed whose IR spectrum included a sharp intense peak near 1700 cm-1 and a broad medium absorption from 2500 to 3300 cm-1. The 1H and 13C NMR spectra are shown. Draw the structure of C6H10 and relate your structure to the observed IR and NMR spectra 14 13 12 11 10 9 8 Chemical shift (ppm) A 3 2 0 250 The signal at 39 ppm is due to the NMR solvent, not the compound of interest. 200 T 150 100 Chemical shift (ppm) 50 T 0
Transcribed Image Text:Question: please help with the following! A compound with the formula C6H10 reacts with one equivalent of Br2 in CCI4. When that same C6H10 compound was treated with a hot, basic solution of KMnO4, followed by acidic workup, a product was formed whose IR spectrum included a sharp intense peak near 1700 cm-1 and a broad medium absorption from 2500 to 3300 cm-1. The 1H and 13C NMR spectra are shown. Draw the structure of C6H10 and relate your structure to the observed IR and NMR spectra 14 13 12 11 10 9 8 Chemical shift (ppm) A 3 2 0 250 The signal at 39 ppm is due to the NMR solvent, not the compound of interest. 200 T 150 100 Chemical shift (ppm) 50 T 0
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