Please help solve part D and E, Here are the answers to the rest of parts: Solution (a) An expression to model the ticket price per person would be : 4.50 + 0.10x This is because the initial price of a ticket is $4.50, and for every increase of $0.10 in the ticket price, the price per person goes up by $0.10. The variable x represents the number of increases in the ticket price, so if x is equal to 2, that means there have been 2 increases in the ticket price, which would make the price per person 4.50 + (0.10 * 2) = $4.70. In other words, the expression 4.50 + (0.10x) takes into account the base price of a ticket and the additional cost added for each increase in the ticket price (represented by x). This makes it a useful model for predicting the ticket price per person. Solution (b) An expression to model the number of people that would attend the circus would be : 1560 - 10x Solution (c) An expression to model the revenue, R, for the circus would be : (4.50 + 0.10x) * (1560 - 10x) This is because the revenue is calculated by multiplying the ticket price per person (modeled by the expression (4.50 + 0.10x) by the number of people who attend the circus (modeled by the expression (1560 - 10x). So let's say x = 2, the ticket price per person would be 4.50 + 0.20 = $4.70 and the number of people who would attend the circus would be 1560 - 20 = 1540 Thus the revenue R would be (4.70 * 1540) = $7238 In other words, the expression (4.50 + 0.10x) * (1560 - 10x) takes into account both the ticket price per person and the number of people who would attend the circus, and multiplies them to give the revenue. This makes it a useful model for predicting the revenue for the circus. This is because the initial number of people that attend the circus is 1560, and for every $0.10 increase in the ticket price, 10 fewer people attend. The variable x represents the number of increases in the ticket price, so if x is equal to 2, that means there have been 2 increases in the ticket price, which would result in 10 fewer people attending per increase. Thus the total number of people would decrease by 20, which is (102), and the expression would be 1560 - (102) = 1458. In other words, the expression (1560 - 10x) takes into account the base number of people attending the circus and the decrease in attendance for each increase in the ticket price (represented by x). This makes it a useful model for predicting the number of people that would attend the circus. Using this please help solve part e and D
Please help solve part D and E, Here are the answers to the rest of parts:
An expression to model the ticket price per person would be :
4.50 + 0.10x
This is because the initial price of a ticket is $4.50, and for every increase of $0.10 in the ticket price, the price per person goes up by $0.10. The variable x represents the number of increases in the ticket price, so if x is equal to 2, that means there have been 2 increases in the ticket price, which would make the price per person 4.50 + (0.10 * 2) = $4.70.
In other words, the expression 4.50 + (0.10x) takes into account the base price of a ticket and the additional cost added for each increase in the ticket price (represented by x). This makes it a useful model for predicting the ticket price per person.
An expression to model the number of people that would attend the circus would be :
1560 - 10x
An expression to model the revenue, R, for the circus would be :
(4.50 + 0.10x) * (1560 - 10x)
This is because the revenue is calculated by multiplying the ticket price per person (modeled by the expression (4.50 + 0.10x) by the number of people who attend the circus (modeled by the expression (1560 - 10x).
So let's say x = 2, the ticket price per person would be 4.50 + 0.20 = $4.70 and the number of people who would attend the circus would be 1560 - 20 = 1540
Thus the revenue R would be (4.70 * 1540) = $7238
In other words, the expression (4.50 + 0.10x) * (1560 - 10x) takes into account both the ticket price per person and the number of people who would attend the circus, and multiplies them to give the revenue. This makes it a useful model for predicting the revenue for the circus.
This is because the initial number of people that attend the circus is 1560, and for every $0.10 increase in the ticket price, 10 fewer people attend. The variable x represents the number of increases in the ticket price, so if x is equal to 2, that means there have been 2 increases in the ticket price, which would result in 10 fewer people attending per increase. Thus the total number of people would decrease by 20, which is (102), and the expression would be 1560 - (102) = 1458.
In other words, the expression (1560 - 10x) takes into account the base number of people attending the circus and the decrease in attendance for each increase in the ticket price (represented by x). This makes it a useful model for predicting the number of people that would attend the circus.
Using this please help solve part e and D
![A ticket to a circus is $4.50. Usually, around 1560 people attend per day. Surveys predict
that for every $0.10 increase in the ticket price, 10 fewer people will attend. Use x to
represent the number of increases in the ticket price.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0594f5c8-4cf7-4c43-885c-b65f7f620919%2F1af569bd-c407-4c62-a45b-f1c2c40646ba%2Fkxp1n6g_processed.png&w=3840&q=75)
![d. Use completing the square to determine the vertex of the revenue function.
e. Use the information in the vertex to determine the maximum revenue, number of
people attending the circus, and the ticket price per person.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0594f5c8-4cf7-4c43-885c-b65f7f620919%2F1af569bd-c407-4c62-a45b-f1c2c40646ba%2Fjffe6ok_processed.png&w=3840&q=75)
![](/static/compass_v2/shared-icons/check-mark.png)
Step by step
Solved in 4 steps
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
![Algebra and Trigonometry (6th Edition)](https://www.bartleby.com/isbn_cover_images/9780134463216/9780134463216_smallCoverImage.gif)
![Contemporary Abstract Algebra](https://www.bartleby.com/isbn_cover_images/9781305657960/9781305657960_smallCoverImage.gif)
![Linear Algebra: A Modern Introduction](https://www.bartleby.com/isbn_cover_images/9781285463247/9781285463247_smallCoverImage.gif)
![Algebra and Trigonometry (6th Edition)](https://www.bartleby.com/isbn_cover_images/9780134463216/9780134463216_smallCoverImage.gif)
![Contemporary Abstract Algebra](https://www.bartleby.com/isbn_cover_images/9781305657960/9781305657960_smallCoverImage.gif)
![Linear Algebra: A Modern Introduction](https://www.bartleby.com/isbn_cover_images/9781285463247/9781285463247_smallCoverImage.gif)
![Algebra And Trigonometry (11th Edition)](https://www.bartleby.com/isbn_cover_images/9780135163078/9780135163078_smallCoverImage.gif)
![Introduction to Linear Algebra, Fifth Edition](https://www.bartleby.com/isbn_cover_images/9780980232776/9780980232776_smallCoverImage.gif)
![College Algebra (Collegiate Math)](https://www.bartleby.com/isbn_cover_images/9780077836344/9780077836344_smallCoverImage.gif)