Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please help
Please find the limiting reagent using the information in the photo
Please show your work using
![given that
Molar Mass of Carl₂ · 2H₂0 = 147.01 g/mol
we need to prepare 20ml solution of 0.200 M.
we
know
Mole
Molarity
Molar Mass X Volume in les
lit
147.01 g/mole x 20 let
1000
0.200 Male/ x 147.01 7/mg x 20 est
mbelete
required to
०४ 0.004 Mole
So
0 200 =
- ها
=
w = 0.588 g
0.200M, 20me solution.
=
و کیا
make
or 0.0044 Mole] required to make 0.220M
Similarly
Molar mass ов к, соз
= 138.21 g/mole
Molanty
0.220 Molellit
=
Molanety
Molow Mass x Volume in lit
W
0.2.20 Mole
138.219/Male
x 20 lit
Tovo
60=
0.220 Mollit X 138.21 8/100/X_20 x lit
Toro
5=
0.608 g
dome solution of K₂ 003.
کیا](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F826a5dfc-503b-435a-b61c-90a3cd1f56dd%2F1ce6578b-6b0a-4eb2-b957-bd4c8b7bde3a%2F5jgjbfb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:given that
Molar Mass of Carl₂ · 2H₂0 = 147.01 g/mol
we need to prepare 20ml solution of 0.200 M.
we
know
Mole
Molarity
Molar Mass X Volume in les
lit
147.01 g/mole x 20 let
1000
0.200 Male/ x 147.01 7/mg x 20 est
mbelete
required to
०४ 0.004 Mole
So
0 200 =
- ها
=
w = 0.588 g
0.200M, 20me solution.
=
و کیا
make
or 0.0044 Mole] required to make 0.220M
Similarly
Molar mass ов к, соз
= 138.21 g/mole
Molanty
0.220 Molellit
=
Molanety
Molow Mass x Volume in lit
W
0.2.20 Mole
138.219/Male
x 20 lit
Tovo
60=
0.220 Mollit X 138.21 8/100/X_20 x lit
Toro
5=
0.608 g
dome solution of K₂ 003.
کیا
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