please help on this python code. Fill in the #lines and what is asking. Write a new code please.
please help on this python code. Fill in the #lines and what is asking. Write a new code please.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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please help on this python code. Fill in the #lines and what is asking. Write a new code please.
![Implement the quadratic_formula) function. The function takes 3 arguments, a, b, and c, and computes the two results of the quadratic
formula:
-b+ v - 4ac
2a
-4ac
2a
The quadratic.formula() function returns the tuple (x1, x2). Ex: When a - 1, b-5, and c- 6, quadratic.formula) retums (3, 2).
Code provided in main.py reads a single input line containing values for a, b, and c, separated by spaces. Each input is converted to a float
and passed to the quadratic.formula) function.
Ex: If the input is
2 -3 -77
the output is:
Solutions to 2x*2 + -3x -77- 0
xl - 7
x2 - -5.50
# TODO: Import math module
def quadratic_formula (a, b, c):
def print_number (number, prefix_str):
if float (int (number)) == number:
print (f'(prefix_str) {number:.0f}')
else:
print (f'{prefix_str) {number:.2f}')
if
name
main
":
input_line = input ()
split line = input_line.split (" ")
a - float (split_line [0])
b - float (split_line (1])
c = float (split_line[2])
solution = quadratic_formula (a, b, c)
print (f'Solutions to {a:.0f}x^2 + (b:.0f}x + {c:.0f} = 0')
print_number (solution [0), 'xl - ')
print_number (solution [1], 'x2 - ')](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1c046fce-56df-4fb7-b9b2-2337f219da1b%2F1b4681cf-3d2e-4832-9b25-baa87199c1de%2Fdnwboqe_processed.png&w=3840&q=75)
Transcribed Image Text:Implement the quadratic_formula) function. The function takes 3 arguments, a, b, and c, and computes the two results of the quadratic
formula:
-b+ v - 4ac
2a
-4ac
2a
The quadratic.formula() function returns the tuple (x1, x2). Ex: When a - 1, b-5, and c- 6, quadratic.formula) retums (3, 2).
Code provided in main.py reads a single input line containing values for a, b, and c, separated by spaces. Each input is converted to a float
and passed to the quadratic.formula) function.
Ex: If the input is
2 -3 -77
the output is:
Solutions to 2x*2 + -3x -77- 0
xl - 7
x2 - -5.50
# TODO: Import math module
def quadratic_formula (a, b, c):
def print_number (number, prefix_str):
if float (int (number)) == number:
print (f'(prefix_str) {number:.0f}')
else:
print (f'{prefix_str) {number:.2f}')
if
name
main
":
input_line = input ()
split line = input_line.split (" ")
a - float (split_line [0])
b - float (split_line (1])
c = float (split_line[2])
solution = quadratic_formula (a, b, c)
print (f'Solutions to {a:.0f}x^2 + (b:.0f}x + {c:.0f} = 0')
print_number (solution [0), 'xl - ')
print_number (solution [1], 'x2 - ')
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