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Please help me, thank you so much. I have underlined what I thought the answer was. The questions are as follows: The switch in the following circuit closes at t = 0 (assume no initial charge on the capacitor).   Determine the voltage, vC(t), and the current, iC(t), prior to the switch closing for t = 0‒   Vc(0-)= 0V because the initial charge is 0 Ic(0-)= 0mA because there is no power supply   Determine the vC(t) and iC(t) after the switch closes and after a long time (i.e. t = 0+ and t = ∞).   Vc(0+)= 0V because the capacitor doesn’t charge instantaneously but increases exponentially. Ic(0+)= Current shoots up to 3.75 mAmps when the switch is closed.   Vc(infinity) = asymptotic limit of 637 volts after increasing exponentially. Ic(infinity) = 0 mA after decreasing exponentially   Determine the time constant, τ, for t > 0.   τ=RC = (0.25uF)*(25.5k ohms) = 0.0063   Write out the equations for the voltage, vC(t), and the current, iC(t), for t > 0. Vc(t)= (637)V(1-e-(t/tau)) Ic(t)= (3.75)mA(e-(t/tau))

Please help me, thank you so much. I have underlined what I thought the answer was. The questions are as follows: The switch in the following circuit closes at t = 0 (assume no initial charge on the capacitor).   Determine the voltage, vC(t), and the current, iC(t), prior to the switch closing for t = 0‒   Vc(0-)= 0V because the initial charge is 0 Ic(0-)= 0mA because there is no power supply   Determine the vC(t) and iC(t) after the switch closes and after a long time (i.e. t = 0+ and t = ∞).   Vc(0+)= 0V because the capacitor doesn’t charge instantaneously but increases exponentially. Ic(0+)= Current shoots up to 3.75 mAmps when the switch is closed.   Vc(infinity) = asymptotic limit of 637 volts after increasing exponentially. Ic(infinity) = 0 mA after decreasing exponentially   Determine the time constant, τ, for t > 0.   τ=RC = (0.25uF)*(25.5k ohms) = 0.0063   Write out the equations for the voltage, vC(t), and the current, iC(t), for t > 0. Vc(t)= (637)V(1-e-(t/tau)) Ic(t)= (3.75)mA(e-(t/tau))

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Please help me, thank you so much. I have underlined what I thought the answer was. The questions are as follows:

  1. The switch in the following circuit closes at t = 0 (assume no initial charge on the capacitor).  
    1. Determine the voltage, vC(t), and the current, iC(t), prior to the switch closing for t = 0‒

 

Vc(0-)= 0V because the initial charge is 0

Ic(0-)= 0mA because there is no power supply

 

    1. Determine the vC(t) and iC(t) after the switch closes and after a long time (i.e. t = 0+ and t = ∞).

 

Vc(0+)= 0V because the capacitor doesn’t charge instantaneously but increases exponentially.

Ic(0+)= Current shoots up to 3.75 mAmps when the switch is closed.

 

Vc(infinity) = asymptotic limit of 637 volts after increasing exponentially.

Ic(infinity) = 0 mA after decreasing exponentially

 

    1. Determine the time constant, τ, for t > 0.

 

τ=RC = (0.25uF)*(25.5k ohms) = 0.0063

 

    1. Write out the equations for the voltage, vC(t), and the current, iC(t), for t > 0.



Vc(t)= (637)V(1-e-(t/tau))

Ic(t)= (3.75)mA(e-(t/tau))

 

thanks again!

50k2 Closes at t = 0 Ic + ·30kΩ 25mA Vc 0.25μF 120k2
Transcribed Image Text:50k2 Closes at t = 0 Ic + ·30kΩ 25mA Vc 0.25μF 120k2
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