Please help me, thank you so much. I have underlined what I thought the answer was. The questions are as follows: The switch in the following circuit closes at t = 0 (assume no initial charge on the capacitor). Determine the voltage, vC(t), and the current, iC(t), prior to the switch closing for t = 0‒ Vc(0-)= 0V because the initial charge is 0 Ic(0-)= 0mA because there is no power supply Determine the vC(t) and iC(t) after the switch closes and after a long time (i.e. t = 0+ and t = ∞). Vc(0+)= 0V because the capacitor doesn’t charge instantaneously but increases exponentially. Ic(0+)= Current shoots up to 3.75 mAmps when the switch is closed. Vc(infinity) = asymptotic limit of 637 volts after increasing exponentially. Ic(infinity) = 0 mA after decreasing exponentially Determine the time constant, τ, for t > 0. τ=RC = (0.25uF)*(25.5k ohms) = 0.0063 Write out the equations for the voltage, vC(t), and the current, iC(t), for t > 0. Vc(t)= (637)V(1-e-(t/tau)) Ic(t)= (3.75)mA(e-(t/tau))
Please help me, thank you so much. I have underlined what I thought the answer was. The questions are as follows: The switch in the following circuit closes at t = 0 (assume no initial charge on the capacitor). Determine the voltage, vC(t), and the current, iC(t), prior to the switch closing for t = 0‒ Vc(0-)= 0V because the initial charge is 0 Ic(0-)= 0mA because there is no power supply Determine the vC(t) and iC(t) after the switch closes and after a long time (i.e. t = 0+ and t = ∞). Vc(0+)= 0V because the capacitor doesn’t charge instantaneously but increases exponentially. Ic(0+)= Current shoots up to 3.75 mAmps when the switch is closed. Vc(infinity) = asymptotic limit of 637 volts after increasing exponentially. Ic(infinity) = 0 mA after decreasing exponentially Determine the time constant, τ, for t > 0. τ=RC = (0.25uF)*(25.5k ohms) = 0.0063 Write out the equations for the voltage, vC(t), and the current, iC(t), for t > 0. Vc(t)= (637)V(1-e-(t/tau)) Ic(t)= (3.75)mA(e-(t/tau))
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Please help me, thank you so much. I have underlined what I thought the answer was. The questions are as follows:
- The switch in the following circuit closes at t = 0 (assume no initial charge on the capacitor).
- Determine the voltage, vC(t), and the current, iC(t), prior to the switch closing for t = 0‒
Vc(0-)= 0V because the initial charge is 0
Ic(0-)= 0mA because there is no power supply
- Determine the vC(t) and iC(t) after the switch closes and after a long time (i.e. t = 0+ and t = ∞).
Vc(0+)= 0V because the capacitor doesn’t charge instantaneously but increases exponentially.
Ic(0+)= Current shoots up to 3.75 mAmps when the switch is closed.
Vc(infinity) = asymptotic limit of 637 volts after increasing exponentially.
Ic(infinity) = 0 mA after decreasing exponentially
- Determine the time constant, τ, for t > 0.
τ=RC = (0.25uF)*(25.5k ohms) = 0.0063
- Write out the equations for the voltage, vC(t), and the current, iC(t), for t > 0.
Vc(t)= (637)V(1-e-(t/tau))
Ic(t)= (3.75)mA(e-(t/tau))
thanks again!
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