Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Please help fill in the rest of the table using the provided data. Show your work.
Transcribed Image Text:|MKMnO₂ = -0.0101 M
Weight of NaBO3 4H₂O(g)
Vol. NaBO3 4H₂O used (mL)
Moles NaBO3 4H₂O (mol)*
Initial buret reading (mL)
Final buret reading (mL)
Volume KMnO4 used (mL)
Moles KMnO4 used (mol)*
Calculated mole ratio (from
starred *values, above) -
i.e. H₂O₂: MnO4
Trial 1
1.0062
10.00
0.0
24.04
24.04
Trial 2
(same) 1
10.00
24.07
24.07
Trial 3
(same) 1
10.00
0.0
24.07
24.07
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Based on the previously asked question and it's data, please help fill in the rest of the table. Show your work. The molarity of KMnO4 is 0.0101M.
Transcribed Image Text:Vol.xver
9.00 mL
"Oxygen bleach
Vol. of aliquot titrated (mL)
Initial buret reading (mL)
Final buret reading (mL)
Volume KMnO4 used (mL)
Moles KMnO4 used (mol)
Moles H₂O₂ in aliquot (mol)
Moles of H₂O₂ in flask (mol)
Mass of H₂O₂ in flask (g)
Percent H₂O₂ in the "oxygen
bleach" - %(w/v) ²
2
mL
Trial 1
Trial 3
7.00
7.00
0.00ml
0.00ml 0.00mL
20.05m 20.03m² 20.04 mi
20.05m 20.03mL 20.04 my
2 Weight-volume percent is defined as g of solute per 100 mL of solution. This is
mathematically identical to
× 100.
Average percent of H₂O2 in the "oxygen bleach"
Relative standard deviation
Trial 2
7.00
%(w/v)
%
Solution
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