Please find bolded info Q (water) = 4.186 Unknown #: III H = q q= mass x specific heat (cs) x change in Tempature (t) Cs = q/ m*t After calculating specific heat go to the table to see what's close to your answer Specific Heat Values of Common Metals: Iron 0.444 J/g ◦C Lead 0.129 J/g ◦C Aluminum 0.890 J/g ◦C Nickel 0.444 J/g ◦C Zinc 0.388 J/g ◦C Copper 0.385 J/g ◦C Water Data: Mass of calorimeter (mass of 1 styrofoam cup): 12.5 g Mass of calorimeter + water: 27.67 g Mass of water: 15.17 g The initial temperature of water: 22°C The final temperature of water: 99.5°C Change in temperature: 77.5 °C The heat released by water: J (Show Calculations) Metal Data: Mass of metal sample: 20.57 g The initial temperature of metal: 99.5 °C (same as the temperature of boiling water) The final temperature of metal: 32 °C Heat gained by metal: J (same as heat released by water) Specific heat of metal: J/g °C (Show Calculations) Identity of metal:
Please find bolded info
Q (water) = 4.186
Unknown #: III
H = q
q= mass x specific heat (cs) x change in Tempature (t)
Cs = q/ m*t
After calculating specific heat go to the table to see what's close to your answer
Specific Heat Values of Common Metals:
Iron 0.444 J/g ◦C
Lead 0.129 J/g ◦C
Aluminum 0.890 J/g ◦C
Nickel 0.444 J/g ◦C
Zinc 0.388 J/g ◦C
Copper 0.385 J/g ◦C
Water Data:
Mass of calorimeter (mass of 1 styrofoam cup): 12.5 g
Mass of calorimeter + water: 27.67 g
Mass of water: 15.17 g
The initial temperature of water: 22°C
The final temperature of water: 99.5°C
Change in temperature: 77.5 °C
The heat released by water: J
(Show Calculations)
Metal Data:
Mass of metal sample: 20.57 g
The initial temperature of metal: 99.5 °C
(same as the temperature of boiling water)
The final temperature of metal: 32 °C
Heat gained by metal: J
(same as heat released by water)
Specific heat of metal: J/g °C
(Show Calculations)
Identity of metal:
Step by step
Solved in 6 steps