Please explain steps in details: Density of water is approximately 1000 kg/m^3 and gravity is 9.81 m/s^2. The function y=x^2 from x = 0 to 2 is rotated about the y-axis. 1) Find the volume of the resulting solid 2) If the resulting solid is filled with water, find the work done in emptying it - assume all units of measurement are in meters. Do we subtract? 3) Find the surface area of the resulting shape (set up the integral, and find a numerical approximation)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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### Detailed Steps for Calculating Rotation of a Solid

**Given:**
- Density of water: \(1000 \, \text{kg/m}^3\)
- Gravity: \(9.81 \, \text{m/s}^2\)

**Function and Rotation:**
- The function \( y = x^2 \) from \( x = 0 \) to \( x = 2 \) is rotated about the y-axis.

#### Tasks:

1. **Find the Volume of the Resulting Solid:**
   - Use the disk or washer method to set up the integral for volume. Integrate with respect to \( x \) from 0 to 2.

2. **Calculate the Work Done in Emptying the Solid Filled with Water:**
   - Assume all units are in meters.
   - Identify how to set up the integral representing work using the formula:

     \[
     \text{Work} = \int_{a}^{b} \rho \, g \, A(y) \, h(y) \, dy
     \]

     Where \(\rho\) is the density, \(g\) is gravity, \(A(y)\) is the area at height \(y\), and \(h(y)\) is the height the water needs to be lifted.

3. **Find the Surface Area of the Resulting Shape:**
   - Set up the integral to find the surface area.
   - Perform the integration to find a numerical approximation.

Include diagrams and calculations for clarity, if applicable, and ensure all steps show how the mathematical concepts are applied.
Transcribed Image Text:### Detailed Steps for Calculating Rotation of a Solid **Given:** - Density of water: \(1000 \, \text{kg/m}^3\) - Gravity: \(9.81 \, \text{m/s}^2\) **Function and Rotation:** - The function \( y = x^2 \) from \( x = 0 \) to \( x = 2 \) is rotated about the y-axis. #### Tasks: 1. **Find the Volume of the Resulting Solid:** - Use the disk or washer method to set up the integral for volume. Integrate with respect to \( x \) from 0 to 2. 2. **Calculate the Work Done in Emptying the Solid Filled with Water:** - Assume all units are in meters. - Identify how to set up the integral representing work using the formula: \[ \text{Work} = \int_{a}^{b} \rho \, g \, A(y) \, h(y) \, dy \] Where \(\rho\) is the density, \(g\) is gravity, \(A(y)\) is the area at height \(y\), and \(h(y)\) is the height the water needs to be lifted. 3. **Find the Surface Area of the Resulting Shape:** - Set up the integral to find the surface area. - Perform the integration to find a numerical approximation. Include diagrams and calculations for clarity, if applicable, and ensure all steps show how the mathematical concepts are applied.
The image represents a coordinate system with a parabola and a horizontal line:

1. **Graphs:**
   - **Parabola**: The equation is \( y = x^2 \). This parabola opens upwards, and its vertex is at the origin (0,0).
   - **Horizontal Line**: The equation is \( y = 4 \). This line is parallel to the x-axis and intersects the parabola.

2. **Points and Intersections:**
   - Intersection points between the parabola and the line are marked at (2,4) and (-2,4).
   - A generic point on the parabola is labeled as \( (x, y) \).

3. **Annotations:**
   - The vertical distance from the x-axis up to the line \( y = 4 \) is marked as 4 units.
   - The distance from any point on the parabola to the line \( y = 4 \) along the vertical direction is marked as \( 4 - y \).
   - There is a horizontal arrow pointing to a disc, labeled “disc of radius x,” on the parabola's interior.

4. **Additional Details:**
   - The points where the parabola intersects the line \( y = 4 \) are highlighted, and their coordinates are given.
   - Vertical lines are drawn from the x-axis to illustrate the height 4, and dashed lines show the level of \( y = 4 \).

This diagram might be used to illustrate concepts related to the intersection of a parabola with a line, as well as discussing the properties of shapes and distances in a coordinate system.
Transcribed Image Text:The image represents a coordinate system with a parabola and a horizontal line: 1. **Graphs:** - **Parabola**: The equation is \( y = x^2 \). This parabola opens upwards, and its vertex is at the origin (0,0). - **Horizontal Line**: The equation is \( y = 4 \). This line is parallel to the x-axis and intersects the parabola. 2. **Points and Intersections:** - Intersection points between the parabola and the line are marked at (2,4) and (-2,4). - A generic point on the parabola is labeled as \( (x, y) \). 3. **Annotations:** - The vertical distance from the x-axis up to the line \( y = 4 \) is marked as 4 units. - The distance from any point on the parabola to the line \( y = 4 \) along the vertical direction is marked as \( 4 - y \). - There is a horizontal arrow pointing to a disc, labeled “disc of radius x,” on the parabola's interior. 4. **Additional Details:** - The points where the parabola intersects the line \( y = 4 \) are highlighted, and their coordinates are given. - Vertical lines are drawn from the x-axis to illustrate the height 4, and dashed lines show the level of \( y = 4 \). This diagram might be used to illustrate concepts related to the intersection of a parabola with a line, as well as discussing the properties of shapes and distances in a coordinate system.
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