Please explain step by step (see attached photo) the process this solution of the running time in Big Oh notation and showing that Master Theorem has proved the answer. The answer is already correct only explanation needed. You can include Master Theorem in your explanation
Please explain step by step (see attached photo) the process this solution of the running time in Big Oh notation and showing that Master Theorem has proved the answer. The answer is already correct only explanation needed. You can include Master Theorem in your explanation
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Please explain step by step (see attached photo) the process this solution of the running time in Big Oh notation and showing that Master Theorem has proved the answer. The answer is already correct only explanation needed. You can include Master Theorem in your explanation
![5 int foo 5 Lint nE
inti,j, sum e0;
Bare Case
TO) OLI) 1
Reunsive Case
Ten) - On) + T(½)
TOn) = n? + TC)
retuin
O(n")
For (i=1; i4=n's; i2){
Tin) = n° +
5n
Tunl = 5()+T(%) - 2 T() ins
Sum 1=j;
in general
T)-(2i+1)nT(")
foo 5 (n/2);
assume that n= 2", k- lagan asi amaches k
TO) = (2k +)n
retarn sum +
+T(A)
Tn) = (2 lagan + 1) (n) + TG)
4
TCm) =2n lag,n +n²
t.
4.
Tin) - nº log, n tn?
+1
Ten)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F49778005-5453-44f8-9998-84ceb681da67%2Fbc38b421-a23f-4d52-b7a5-f0a099d1c417%2Fvin41pm_processed.png&w=3840&q=75)
Transcribed Image Text:5 int foo 5 Lint nE
inti,j, sum e0;
Bare Case
TO) OLI) 1
Reunsive Case
Ten) - On) + T(½)
TOn) = n? + TC)
retuin
O(n")
For (i=1; i4=n's; i2){
Tin) = n° +
5n
Tunl = 5()+T(%) - 2 T() ins
Sum 1=j;
in general
T)-(2i+1)nT(")
foo 5 (n/2);
assume that n= 2", k- lagan asi amaches k
TO) = (2k +)n
retarn sum +
+T(A)
Tn) = (2 lagan + 1) (n) + TG)
4
TCm) =2n lag,n +n²
t.
4.
Tin) - nº log, n tn?
+1
Ten)
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