Please draw ERD for the company with 5 entities + show the relation Thanks
Q: воок Book id Title Publisher_name 444 BOOK AUTHORSs Book id Author_name PUBLISHER Name Address Phone
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Q: how do i create a scalar valued functionto get the total cost of the UnitCost in the ProductsTable
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Q: If an employee can work for only one department and a department can have many employees (one to…
A: Dear learner, hope you are doing well, I will try my best to answer this question. Thank you!
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Q: Report the eid of every employee who manages at least two different people. Use the usual technique…
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Q: convert this EERD to relation.
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- NORMALIZATION EXERCISE Based on the given relation schema below, perform normalization up to 3NF. Write your answer in below space ORDER (Order_ID,Date,Cust_ID,Cust_Name,State,City,ItemNO,ItemDescription,ItemPrice,Quantity) 1NF 2NF 3NFhow do i create a scalar valued functionto get the total cost of the UnitCost in the ProductsTable Create table Products( ProductID int primary key, CategoryID varchar (200), MobileNumber varchar(200), ModelName varchar (200), ProductImage varchar (200), UnitCost varchar (200), Description varchar (200), );insert into Products(ProductID,CategoryID,MobileNumber,ModelName,ProductImage,UnitCost,Description)values(1000,'011','1-758-914-0628','RobotDestroyer','Robot Image','R79.60','The new RobotDestroyer defender of the universe')insert into Products(ProductID,CategoryID,MobileNumber,ModelName,ProductImage,UnitCost,Description)values(2000,'012','(701) 754-5550','GardenSpade','GardenSpadeImage','R50.90','Guaranteed to get the toughest weeds out')insert into Products(ProductID,CategoryID,MobileNumber,ModelName,ProductImage,UnitCost,Description)values(3000,'013','(723) 280-3358','Broom','Broom Image','R78.92','The best broom you will ever need with new ergonomic…Report the eid of every employee who manages at least two different people. Use the usual technique of table renaming and self-join, except use the keywords CROSS JOIN to take the Cartesian product of the two tables: sales(eid, day, amount)employee(eid, name, salary, dept)manages(manager, junior)department(did, name, division)employee[dept] ⊆ department[did]manages[manager] ⊆ employee[eid]manages[junior] ⊆ employee[eid]sales[eid] ⊆ employee[eid] USE CROSS JOIN PLEASE! Only Cross Join is allowed. Do not use other SQL techniques please.
- Given the following relation that stores details of student registration: Stu_ID Name Town Province Course RegisteredDate S101 Malak Al Nadabi Al Khuwair Western ITDR2106 02-02-2020 S101 Malak Al Nadabi Al Khuwair Western ITDR1105 14-09-2019 S102 Nadar Al Hashli Daesit Southern ITDR1102 05-02-2020 S102 Nadar Al Hashli Daesit Southern ITDR1101 05-02-2020 S103 Basit Barkat Ruwi Central ITDR1105 06-02-2020 S104 Yeshan Al Khuwair Western ITDR2106 15-09-2019 If the functional dependencies are consistent with the above relation, put TRUE. If they are not, put FALSE. Stu_ID à Name, Town Town à Province Course à RegisteredDate RegisteredDate à Course Stu_ID, Course à RegisteredDate Stu_ID à Course Stu_IDIf you assume that a relation has no duplicate data, how do you know there is always at least one primary key?Find the relation algebra query based on the SQL given.
- Answer with handEmployeeID is the primary key for the relation below. Which column violates a rule (characteristic) of a relation? Employee Relation EmployeeID Department PhoneNum PhoneNum 300 Finance 321-299-1234 407-999-2300 200 Sales 407-222-9090 321-365-0912 400 Sales 407-807-1124 407-453-2294 100 HR 321-934-2034 Group of answer choices The column named PhoneNum because you can’t have two columns with the same name. All the columns are valid. The EmployeeID column because the ID numbers are not in order. The Department column.If an employee can work for only one department and a department can have many employees (one to many relationship). Which answer the relationship table "work" that has the best values to describe the relationship between employee and department? The employee table has two columns (eid, name) with records ('E1','A'), ('E2','B'), ('E3','C'). The department table has two columns (did, name) with records ('D1','X'), ('D2','Y'), ('D3', 'Z'). work(eid, did) with values ('E1','D1'), ('E1','D2'), ('E2,'D2'). work(eid, did) with values ('E1','D1'), ('E2','D2'), ('E3,'D2'). work(eid, did) with values ('E1','D1'), ('E2','D2'), ('E2,'D3'). work(eid, did) with values ('E1','D1'), ('E2','D2'), ('E3,'D3').
- The set of output data in a relationship is called the direct variation range domain function notationGiven two relations x(A,B,C,D) and y(B,C,E,F). Without using outer join expression, write a SQL query that is equivalent to select * from x natural right outer join y;After setting up all relations, you need to apply following queries to get data from givenrelations: (Write queries and also paste screenshots in answer file) Get all the employees work with ‘Martin’ or ‘Scott’ in their departments. Get all employees work under management of ‘Blake’. Sort in descending order withrespect to employee number. Get all employees with letter ‘A’ in their name, who work in New York.Get all employees data whom salaries are more than combined salaries of Adams andSmith. Using oracle APEX we are creating a table now - CREATE TABLE DEPT( DEPTNO NUMBER(10) NOT NULL, DNAME VARCHAR(50) NOT NULL, LOC VARCHAR2(30), CONSTRAINT DEPT_PK PRIMARY KEY (DEPTNO) ); We use NOT NULL constraint to make the cell occupied with something related to column line for example; we can see a lot of applications where we see (field is mandatory) Step 2 NOW EMP TABLE- CREATE TABLE EMP( EMPNO NUMBER(10)NOT NULL, ENAME VARCHAR2(50)NOT NULL, JOB VARCHAR2(50), MGR VARCHAR2(50),…
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