Please draw a standard flowchart with their correct diagram representation for the c++ program below #include #include int main() { double a, b, c; double discriminant, root1, root2; std::cout << "Enter the coefficients of the quadratic equation (a, b, c): "; std::cin >> a >> b >> c; discriminant = b * b - 4 * a * c; if (discriminant > 0) { root1 = (-b + sqrt(discriminant)) / (2 * a); root2 = (-b - sqrt(discriminant)) / (2 * a); std::cout << "The roots of the equation are: " << root1 << " and " << root2 << std::endl; } else if (discriminant == 0) { root1 = -b / (2 * a); std::cout << "The root of the equation is: " << root1 << std::endl; } else { std::cout << "The roots of the equation are complex" << std::endl; } return 0; }
Please draw a standard flowchart with their correct diagram representation for the c++ program below #include #include int main() { double a, b, c; double discriminant, root1, root2; std::cout << "Enter the coefficients of the quadratic equation (a, b, c): "; std::cin >> a >> b >> c; discriminant = b * b - 4 * a * c; if (discriminant > 0) { root1 = (-b + sqrt(discriminant)) / (2 * a); root2 = (-b - sqrt(discriminant)) / (2 * a); std::cout << "The roots of the equation are: " << root1 << " and " << root2 << std::endl; } else if (discriminant == 0) { root1 = -b / (2 * a); std::cout << "The root of the equation is: " << root1 << std::endl; } else { std::cout << "The roots of the equation are complex" << std::endl; } return 0; }
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
Please draw a standard flowchart with their correct diagram representation for the c++ program below
#include
#include
int main() {
double a, b, c;
double discriminant, root1, root2;
std::cout << "Enter the coefficients of the quadratic equation (a, b, c): ";
std::cin >> a >> b >> c;
discriminant = b * b - 4 * a * c;
if (discriminant > 0) {
root1 = (-b + sqrt(discriminant)) / (2 * a);
root2 = (-b - sqrt(discriminant)) / (2 * a);
std::cout << "The roots of the equation are: " << root1 << " and " << root2 << std::endl;
} else if (discriminant == 0) {
root1 = -b / (2 * a);
std::cout << "The root of the equation is: " << root1 << std::endl;
} else {
std::cout << "The roots of the equation are complex" << std::endl;
}
return 0;
}
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