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Please complete coding assignment in Python

Please complete coding assignment in Python

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Please complete coding assignment in Python! Thank you!

import numpy as np def bilinear_interp(query, X, Y, Z): """Bi-linear interpolation on two-dimensional grid. Parameters query tuple, (x,y) Coordinates of query point to interpolate X 1d array of length m, *sorted strictly ascending* Coordinates of data points along first dimension Y 1d array of length n, *sorted strictly ascending* Coordinates of data points along second dimension Z 2d array of shape (m, n) I Values of the dependent variable z on data points. Z[i, j] is the value of z at the data point with coordinates (✗[i], Y[j]). Returns zqscalar Interpolated z value on query point. Bi-linear interpolation uses a weighted average of values from the 4 nearest neighbor data points. Interpolated value always equals data value if query point is a data point. If query point is outside data range the interpolated value is np.nan. (X.size, Y.size)),\ "I assert (X.ndim == Y.ndim == 1) and (Z.shape "Dimension mismatch, check the docstring.' m, nZ.shape x, y query zq = 0 ### START YOUR CODE HERE ### ### ### STEP 0: get the easy stuff out of the way. If the query point is "out #3#23% of bounds", just return the special value np.nan. ### ### STEP 1a: Find i such that X[i] <= x < X[i+1] ### STEP 1b: Find j such that Y[j] <= y < Y[j+1] ### ### There are many ways of doing this, and I don't require your solution to ### be similar to mine. The goal is to get the correct indices ### in ALL cases. (Note that the interpolation formula below works just as %%% well if the condition is changed to X[i] < x <= X[i+1], and the same %23% 23%23 for y of course. So if a query coordinate is equal to the largest data ### coordinate you are technically using that second condition.) ### ### STEP 2: Use bi-linear interpolation formula to calculate and return the ### interpolated value. ### THAT'S IT ##########1 return zq ##########
Transcribed Image Text:import numpy as np def bilinear_interp(query, X, Y, Z): """Bi-linear interpolation on two-dimensional grid. Parameters query tuple, (x,y) Coordinates of query point to interpolate X 1d array of length m, *sorted strictly ascending* Coordinates of data points along first dimension Y 1d array of length n, *sorted strictly ascending* Coordinates of data points along second dimension Z 2d array of shape (m, n) I Values of the dependent variable z on data points. Z[i, j] is the value of z at the data point with coordinates (✗[i], Y[j]). Returns zqscalar Interpolated z value on query point. Bi-linear interpolation uses a weighted average of values from the 4 nearest neighbor data points. Interpolated value always equals data value if query point is a data point. If query point is outside data range the interpolated value is np.nan. (X.size, Y.size)),\ "I assert (X.ndim == Y.ndim == 1) and (Z.shape "Dimension mismatch, check the docstring.' m, nZ.shape x, y query zq = 0 ### START YOUR CODE HERE ### ### ### STEP 0: get the easy stuff out of the way. If the query point is "out #3#23% of bounds", just return the special value np.nan. ### ### STEP 1a: Find i such that X[i] <= x < X[i+1] ### STEP 1b: Find j such that Y[j] <= y < Y[j+1] ### ### There are many ways of doing this, and I don't require your solution to ### be similar to mine. The goal is to get the correct indices ### in ALL cases. (Note that the interpolation formula below works just as %%% well if the condition is changed to X[i] < x <= X[i+1], and the same %23% 23%23 for y of course. So if a query coordinate is equal to the largest data ### coordinate you are technically using that second condition.) ### ### STEP 2: Use bi-linear interpolation formula to calculate and return the ### interpolated value. ### THAT'S IT ##########1 return zq ##########
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