Please answer question four number 4 Now rewrite the equation that it is solved for the height of the wood above the equilibrium

College Physics
11th Edition
ISBN:9781305952300
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Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please answer question four

number 4 Now rewrite the equation that it is solved for the height of the wood above the equilibrium 

vood, measure their mas
measurements in the table below and on the
measure the amount of each block that is above and below the equilibrium w
Y*
Hbelow /
Height Height
Density
above
below
Height
(cm)
Htotal
Width Length Volume
(cm)
pe of
Mass
water
water
(P)
(g/cm³)
vpoa
(g)
(cm)
(cm³)
Pwood/
Habove
(cm)
Hbelow
(cm)
Htotal
***
Pwater**
51.7 918.24 295.20.5159 1.9913.211.21013
295.2/0.5158 1.94 3.2 1.20.13
wood
159.7
ne
166.6/059
8.7 8.62.21646|1.01210.99 2921
ak
l84.2 10.5 10.2 3.4 378.430.505 |.9812.9|1.60.15s
^You and your partner only need to measure two wood types, but you should record data for other wood types to
include on your graph. All you need to record for those is X and Y.
* These are the columns you will graph. The values in these columns should be expressed as decimals.
** The density of water is 1 g/cm?
*** Htotal Should come from the third column.
1. Graph columns X and Y on the next page. Label your axes, graphing the column labeled X on the
X-axis and Y on the y-axis.
2. Based on the graph, describe the relationship between the density ratios and the height ratios. See
Figure 3.
3. Write an equation that expresses how the density of the wood block relates to the height of the
block below the equilibrium line. The only thing on the left-hand side of the equation should be
Hbelow. (Remember: The wood block is floating in equilibrium when it has displaced a volume of
water that has the same mass as the entire wood block. If the wood block is 80% as dense as
water, then 80% of the block will sit below the water line.)
PwordHiotal
Pwater
Hyelow
4. Now rewrite the equation so that it is solved for the height of the wood block above the
equilibrium line.
-2-
Transcribed Image Text:vood, measure their mas measurements in the table below and on the measure the amount of each block that is above and below the equilibrium w Y* Hbelow / Height Height Density above below Height (cm) Htotal Width Length Volume (cm) pe of Mass water water (P) (g/cm³) vpoa (g) (cm) (cm³) Pwood/ Habove (cm) Hbelow (cm) Htotal *** Pwater** 51.7 918.24 295.20.5159 1.9913.211.21013 295.2/0.5158 1.94 3.2 1.20.13 wood 159.7 ne 166.6/059 8.7 8.62.21646|1.01210.99 2921 ak l84.2 10.5 10.2 3.4 378.430.505 |.9812.9|1.60.15s ^You and your partner only need to measure two wood types, but you should record data for other wood types to include on your graph. All you need to record for those is X and Y. * These are the columns you will graph. The values in these columns should be expressed as decimals. ** The density of water is 1 g/cm? *** Htotal Should come from the third column. 1. Graph columns X and Y on the next page. Label your axes, graphing the column labeled X on the X-axis and Y on the y-axis. 2. Based on the graph, describe the relationship between the density ratios and the height ratios. See Figure 3. 3. Write an equation that expresses how the density of the wood block relates to the height of the block below the equilibrium line. The only thing on the left-hand side of the equation should be Hbelow. (Remember: The wood block is floating in equilibrium when it has displaced a volume of water that has the same mass as the entire wood block. If the wood block is 80% as dense as water, then 80% of the block will sit below the water line.) PwordHiotal Pwater Hyelow 4. Now rewrite the equation so that it is solved for the height of the wood block above the equilibrium line. -2-
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