(PLAYING WITH A VENN DIAGRAM)AВConsider the given Venn diagram with threeindependent events A, B, and C such thatP(A) = 0.3, P(B) = 0.4, and P(C) = 0.1.an appropriate formulaeprobabilities of the events:UsetofindtheVenn diagramv (ANBN ce)A. 0.42B. 0.36|(ANB)С. 0.88v (ANBe)D. 0.42(ACUBC)E. 0.88v (AUB) ABConsider the given Venn diagram with threeindependent events A, B, and C such thatP(A) = 0.3, P(B) = 0.4, and P(C)= 0.1.an appropriate formulaeprobabilities of the events:Usetofind theVenn diagramA. 0.4000(ANB)B. 0.1000v (ANC)-C. 0.04v (BNC)D. 0.34v (ANBNC)-E. 0.40v (AUB)-F. 0.3000v (AUC)G. 0.64v (BUC)H. 0.22v (AUBUC)I. 0.0v (ANBUC)J. 0.12v (AUBNC)К. 0.0L. 0.58M. 0.46

Name: (PLAYING WITH A VENN DIAGRAM)AВConsider the given Venn diagram with t
Uploaded: 2024-03-20T07:07:50.000Z
Channel: Bartleby
Description: (PLAYING WITH A VENN DIAGRAM)AВConsider the given Venn diagram with threeindependent events A, B, and C such thatP(A) = 0.3, P(B) = 0.4, and P(C) = 0.1.an appropriate formulaeprobabilities of the events:UsetofindtheVenn diagramv (ANBN ce)A. 0.42B. 0

Step 1: Since you have posted a question with multiple subparts, we will solve the first three parts…

Math

Statistics

(PLAYING WITH A VENN DIAGRAM) A В Consider the given Venn diagram with three independent events A, B, and C such that P(A) = 0.3, P(B) = 0.4, and P(C)= 0.1. an appropriate formulae probabilities of the events: Use to find the Venn diagram A. 0.42 - v (ANB) B. 0.36 C. 0.88 · v (ACNB) D. 0.42 v (A°UB) E. 0.88 - v (AUB)

(PLAYING WITH A VENN DIAGRAM) A В Consider the given Venn diagram with three independent events A, B, and C such that P(A) = 0.3, P(B) = 0.4, and P(C)= 0.1. an appropriate formulae probabilities of the events: Use to find the Venn diagram A. 0.42 - v (ANB) B. 0.36 C. 0.88 · v (ACNB) D. 0.42 v (A°UB) E. 0.88 - v (AUB)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A and B are independent events. Use the following probabilities to answer the question. Round to 4 decimal places. P(A) = 0.6, P(A and B) = 0.49, find P(B) P(B) =
A and B are independent events. Use the following probabilities to answer the question. Round to 4 decimal places. P(A) = 0.17, P(A and B) = 0.11, find P(B) P(B) = ?
A and B are independent events. Use the following probabilities to answer the question. Round to 4 decimal places. P(A) = 0.58, P(A and B) = 0.02, find P(B) P(B) =
Suppose a sitcom is filmed on set between zero and five days per week. The following table shows the probabilities of the sitcom being filmed zero, one, two, three, four, or five days in a week. ? ?(?) 0 0.112131 0.145582 0.169423 0.225474 0.153755 0.19365The expected number of days the sitcom will be filmed in one week, ? , is 2.74408. Use the formula below to calculate the variance, ?2, of the number days the sitcom films, ?, where ?(?) is the probability of the sitcom filming for a particular number of days.?2=∑[(?−?)2⋅?(?)]Provide each answer with three decimal places of precision. What is the weighted probability of zero days of filming?(?0−?)2⋅?(?0)= What is the weighted probability of one day of filming?(?1−?)2⋅?(?1)= What is the weighted probability of two days of filming?(?2−?)2⋅?(?2)= What is the weighted probability of three days of filming?(?3−?)2⋅?(?3)= What is the weighted probability of four days of filming?(?4−?)2⋅?(?4)= What is the weighted probability of five days of…
1 Rank the probabilities of 10%, 5, and 0.06 from the most likely to occur to the least likely to occur. O a Ob O c Od 1 0.06, 5, 10% 1 5, 10%, 0.06 1 10%, 5, 0.06 0.06, 10%, 5
Q. 2 A car dealer notes the following probabilities about his customers: P(those who buy a new car) = 0.25 P(those who buy a European car) = 0.30 P(those who neither buy a new car nor an European car) = 0.54 Find the probability that next customer buys a new European car?
An experiment can result in one of five equally likely simple events, E,, E, E. Events A, B, and C are defined as follows. A: E,, E, P(A) = 0.4 B: E,, E E E, P(B) = 0.8 C: E,. E, P(C) = 0.4 Refer to the following probabilities. P(AN B) = 0.2 P(A|B) = 0.25 P(B|A) = 0.5 P(B U C) = 1 P(B|C) = 0.5 P(C|B) = 0.25 Use the Addition and Multiplication Rules to find the following probabilities. (a) P(A U B) P(A U B) = --Select-- v+ --Select-- ---Select-- v %3D (b) P(ANB) P(ANB) =-Select-- v P(B) = (c) P(B nC) P(BnC) = -Select-- V- P(C) = Do the results agree with those obtained by listing the simple events in each? P(A U B) = P({E, E, E,, E, E;}) = 1 P(A N B) = P({E,}) = 0.2 P(Bn C) = P({E,}) = 0.2 O Yes O No
Given 3 dice each with the numbers 1 through 6 but with probabilities as follows : Die I: f(x)=1/6 Die II: f(x)=x/21 Die III: f(x)=x2/91 A die is selected, tossed and 5 appears. What is the probability that it is Die I ? A.90/380 B.91/371 C.85/375 D.95/381
Q. 2 A car dealer notes the following probabilities about his customers: P(those who buy a new car ) = 0.25 P(those who buy a European car) = 0.30 P(those who neither buy a new car nor an European car ) = 0.58 Find the probability that next customer buys a new European car?
Please answer part C
If ? and ? are two mutually exclusive events with ?(?)=0.2 and ?(?)=0.7, find the following probabilities: by the way, what's the c and d mean like Both A and B have A horizontal line over their heads
Can someone help me out with these questions.