Plants and animals burn carbohydrates inside their cell to release energy. This process is called oxidation/respiration, represented by the equation below . If 45.90 mol of glucose (C6H1206) is present during oxidation process, how many moles of carbon dioxide are produced? * C6H1206 + 6 O2 → 6 CO2 + 6 H2O

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Plants and animals burn carbohydrates
inside their cell to release energy. This
process is called oxidation/respiration,
represented by the equation below. If 45.90
mol of glucose (C6H1206) is present during
oxidation process, how many moles of
carbon dioxide are produced? *
C6H1206 + 6 O2 → 6 CO2 + 6 H20
Transcribed Image Text:Plants and animals burn carbohydrates inside their cell to release energy. This process is called oxidation/respiration, represented by the equation below. If 45.90 mol of glucose (C6H1206) is present during oxidation process, how many moles of carbon dioxide are produced? * C6H1206 + 6 O2 → 6 CO2 + 6 H20
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